1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
3 years ago
5

(04.02 MC)

Chemistry
1 answer:
bagirrra123 [75]3 years ago
5 0

Answer:

it is carboan

Explanation:

You might be interested in
What is the density of chlorine gas (MM = 71.0glmol) at 1.50 atm and 25.0C
IrinaVladis [17]

Answer: D=4.35g/L

Explanation:

The formula for density is D=\frac{M}{V}. M is mass in grams and V is volume in liters.

Since we are give pressure and temperature, we can use the ideal gas law to find moles/volume. FInding moles/volume would give us the base for density. All we would have to do is convert moles to grams.

Ideal Gas Law: PV=nRT

\frac{n}{V} =\frac{P}{RT}

\frac{n}{V}=\frac{1.50 atm}{(0.08206Latm/Kmol)(25+274.15K)}

\frac{n}{V} =\frac{0.061309mol}{L}

Now that we have moles, we can use molar mass of chlorine gas to find grams.

0.061309mol*\frac{71.0g}{mol} =4.3529g

With our grams, we can find our density.

D=\frac{4.3529g}{L}

We need correct significant figures so our density is:

D=\frac{4.35g}{L}

5 0
3 years ago
As a central atom, sulfur can take more than eight electrons in its valence shell.
vodka [1.7K]

Sulphur is located in the third period and group 16. The general electronic configuration of group 16 is ns^{2} np^{4} therefore the maximum number of valency electrons in group 16 is 6. The electronic configuration of sulphur is [Ne] 3s^{2} 3p^{4}3d^{0}. Sulphur has six valency electrons whereas sulphur can have more than eight electrons in its valency shell as it have an empty d-shell electrons can accumulate in the empty d-shell. The complete d-shell and the P_{z} orbital will be empty. As each orbital can accept 2 electrons, sulphur can have 12 valency electrons in its valency shell.

3 0
3 years ago
Read 2 more answers
Use the ball and stick models above. If you had a gram of water and a gram of
Sladkaya [172]

Answer:

When the weather is nice, many people begin to work on their yards and homes. For many projects, sand is needed as a foundation for a walk or to add to other materials. You could order up twenty million grains of sand and have people really stare at you. You could order by the pound, but that takes a lot of time weighing out. The best bet is to order by the yard, meaning a cubic yard. The loader can easily scoop up what you need and put it directly in your truck.

Avogadro’s Number

It certainly is easy to count bananas or to count elephants (as long as you stay out of their way). However, you would be counting grains of sugar from your sugar canister for a long, long time. Atoms and molecules are extremely small – far, far smaller than grains of sugar. Counting atoms or molecules is not only unwise, it is absolutely impossible. One drop of water contains about 10 22 molecules of water. If you counted 10 molecules every second for 50 years without stopping you would have counted only 1.6 × 10 10 molecules. Put another way, at that counting rate, it would take you over 30 trillion years to count the water molecules in one tiny drop.

Explanation:

6 0
2 years ago
A 17.6-g sample of ammonium carbonate contains ________ mol of ammonium ions.
postnew [5]
These problems are a bit interesting. :)

First let's write the molecular formula for ammonium carbonate. 

NH4CO3 (Note! The 4 and 3 are subscripts, and not coefficients)

17.6 gNH4CO3

Now to convert to mol of one of our substances we take the percent composition of that particular part of the molecule and multiply it by our starting mass. This is what it looks like using dimensional analyse. 

17.6 gNH4CO3 * (Molar Mass of NH4 / Molar Mass of NH4CO3)

Grab a periodic table (or look one up) and find the molar masses for these molecules! Well. In this case I'll do it for you. (Note: I round the molar masses off to two decimal places)

NH4 = 14.01 + 4*1.01 = 18.05 g/mol
NH4CO3 = 14.01 + 4*1.01 + 12.01 + 3*16.00 = 78.06 g/mol


17.6 gNH4CO3 * (18.05 molNH4 / 78.06 molNH4CO3)
= 4.07 gNH4

Now just take the molar mass we found to convert that amount into moles!

4.07 gNH4 * (1 molNH4 / 18.05 gNH4) = 0.225 molNH4

4 0
2 years ago
What volume of lead (of density 11.3 g/cm3 ) has the same mass as 395 cm3 of a piece of redwood (of density 0.38 g/cm3 )? Answer
Zepler [3.9K]
d_{1}=\frac{m}{V_{1}}\\\\
V_{1}=395cm^{3}\\
d_{1}=0,38\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ m=395cm^{3}*0,38\frac{g}{cm^{3}}=150,1g\\\\\\
d_{2}=\frac{m}{V_{2}}\\\\
m=150,1g\\
d_{2}=11,3\frac{g}{cm^{3}} \ \ \ \ \Rightarrow \ \ \ \ V_{2}=\frac{150,1g}{11,3\frac{g}{cm^{3}}}\approx13,28cm^{3}
8 0
3 years ago
Other questions:
  • A human lung at maximum capacity has a volume of 3.0 liters. If the partial pressure of oxygen in the air is 21.1 kilopascals an
    13·1 answer
  • What happens to acetone molecules when you add heat to a beaker of liquid acetone?
    10·1 answer
  • Which situation would be considered pseudoscience?
    11·2 answers
  • Select the correct answer from each drop-down menu.
    13·1 answer
  • Which of the following has the highest pH?
    13·1 answer
  • Oil floats on the surface of water but mercury sinks. why?​
    8·1 answer
  • While investigating greenhouse gases, I measured 0.1875 grams of carbon dioxide in a 500-gram sample of the atmosphere. What is
    10·1 answer
  • What is one ecosystem you can think of? What non-living and living things are found in your ecosystem?
    11·1 answer
  • WILL MARK BRAINLIEST! PLEASE HELP!!
    5·1 answer
  • Please help this is very important​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!