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Alex777 [14]
3 years ago
11

How many grams are in 1.11 moles of manganese sulfate, Mn3(SO4)7?

Chemistry
2 answers:
UNO [17]3 years ago
8 0
The correct answer is 167.60889
UNO [17]3 years ago
6 0

Answer:

There are 167.60889 grams in 1.11 moles of manganese sulfate. The molecular formula of manganese sulfate is MnSO4.

Explanation:

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Calculate the pressure of 2.50 Liters of a gas at 25.0oC if it has a volume of 4.50 Liters at
MariettaO [177]

Answer:

P_2 =0.51  atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

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Pressure P2 = ??

Using combined gas law:

\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}

0.008389261745 \times 273 = 4.5P_2

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4 0
2 years ago
In which way does a na1+ ion differ from a neutral na atom?
DochEvi [55]
Na 1+ misses 1 electron
8 0
3 years ago
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suter [353]

Answer:

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Explanation:

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Chlorine can be prepared in the laboratory by oxidation of hydrochloric acid using KMnO4 as follows;

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3 years ago
Name the noble gas atom that has the same electron configuration as each ion in the compound rubidium oxide
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Explanation:

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