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Alex777 [14]
2 years ago
11

How many grams are in 1.11 moles of manganese sulfate, Mn3(SO4)7?

Chemistry
2 answers:
UNO [17]2 years ago
8 0
The correct answer is 167.60889
UNO [17]2 years ago
6 0

Answer:

There are 167.60889 grams in 1.11 moles of manganese sulfate. The molecular formula of manganese sulfate is MnSO4.

Explanation:

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svet-max [94.6K]

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A. covalent bond

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4 0
2 years ago
A titration was performed in a lab situation. H2SO4 was titrated with NaOH. The following data was collected: mL of NaOH used =
RoseWind [281]
For the titration we use the equation,
                             M₁V₁ = M₂V₂
where M is molarity and V is volume. Substituting the known values,
                            (0.15 M)(43.2 mL) = (2)(M₂)(20.5 mL)
We multiply the right term by 2 because of the number of H+ in H2SO4. Calculating for M₂ will give us 0.158 M. Thus, the answer is approximately 0.16M. 
7 0
3 years ago
Read 2 more answers
Gases present in atmosphere are in ionic form true or false​
ANTONII [103]

Answer:

false

Explanation:

Only ionic compounds can dissolate in water.

6 0
3 years ago
Is reacts with acid a chemical or physical property? (WORTH 30 Points.)
Alborosie

Answer:

Metals in general have they chemical property of reacting with an acid. Zinc reacts with hydrochloric acid to produce hydrogen gas. This is a chemical property. Chemical change results in one or more substances of entirely different composition from the original substances.

3 0
3 years ago
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What masses of kbr and water are needed to produce 300. g of a solution that is 3.00 % by mass?
attashe74 [19]
In a solution of KBr and water; KBr is the solute and water is the solvent;
Therefore; to achieve 3% by mass; it means we are going to have 3% of the mass being the solute and the other 97 % being the solvent.
Thus; KBr (solute) = 3/100 × 300 (total mass) = 9 g
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8 0
2 years ago
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