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Alex777 [14]
3 years ago
11

How many grams are in 1.11 moles of manganese sulfate, Mn3(SO4)7?

Chemistry
2 answers:
UNO [17]3 years ago
8 0
The correct answer is 167.60889
UNO [17]3 years ago
6 0

Answer:

There are 167.60889 grams in 1.11 moles of manganese sulfate. The molecular formula of manganese sulfate is MnSO4.

Explanation:

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<h3>Further explanation</h3>

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

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V = volume, liter  

n = number of moles  

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The pressure :

\tt P=\dfrac{nRT}{V}\\\\n=\dfrac{1.5\times 0.082\times 285}{30}\\\\P=1.1685~atm

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