The correct answer to this problem would be that like poles repel and unlike poles attract.
N and N poles repel
S and S poles repel
N and S poles attract
S and N poles attract
Answer: D) like poles repel each other. unlike poles attract each other
I hope this helps!
We can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.
<h3>How we can calculate the thickness using screw gauge?</h3>
We can determine the width/thickness of a coin by using a screw gauge because screw gauge is an instrument that measures thickness of an object that are very thin. First we can placed the coin in between the teeth of the gauge and then move the gauge until the coin can be held tightly. After that note the reading on the scale.
So we can conclude that we can calculate the width/thickness of a coin using a screw gauge by placing it in between the teeth of the gauge.
Learn more about thickness here: brainly.com/question/4937019
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Answer:
l = 10.16 m
Explanation:
In this case, we have the period of oscillation of the pendulum is 6.4 s. It is required to find the height of the tower.
We know that the pendulum executes SHM. Let l is the height of the tower. The time period of simple pendulum is given by :
g is acceleration due to gravity
We need to rearrange the above equation such that,
So, the height of the tower is 10.16 m.
Answer:
1. 60 m/s.
2. 3600 m.
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Time (t) = 2 mins
Final Velocity (v) =?
Distance travelled (s) =?
1. Determination of the velocity at the end of 2 minutes.
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Time (t) = 2 mins = 2 x 60 = 120 secs
Final Velocity (v) =?
v = u + at
v = 0 + (0.5 x 120)
v = 60 m/s
Therefore, the velocity at the end of 2 minutes is 60 m/s.
2. Determination of the distance travelled.
Initial velocity (u) = 0
Acceleration (a) = 0.5 m/s²
Final velocity (v) = 60 m/s
Distance travelled (s) =..?
v² = u² + 2as
60² = 0 + 2 x 0.5 x s
3600 = 1 x s
s = 3600 m
Therefore, the distance travelled is 3600 m.
