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3 years ago

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Asexual reproduction involves only one parent. The offspring of this type of reproduction have - F DNA identical to the DNA of t

he parent C One-half of the DNA of the parent H DNA that is different from the parent 0 DNA that is incomplete

1 answer:

Sedbober [7]3 years ago

5 0

Answer:

DNA identical to the DNA of the parent

Explanation:

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What do astronomers mean when they say that we are all star stuff?.

tekilochka [14]

Answer:

low-mass star.

Explanation:

Pls, choose me as brainliest!

7 0

3 years ago

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3.) Brady walks 5 meters forward, turns right, walks 25 meters, turns right again, walks 5

Triss [41]

Answer:

Distance covered is: 45 meters

Displacement is 15 meters to the right of where he started

Explanation:

Notice that Brady has walk a path that looks like an incomplete rectangle of height 5 meters and length 25meters, although he actually didn't cover the full length (25 meters) when getting back to the point where he started (he made just 10 meters instead of 25 after the third turn right) See attached image.

Therefore, Brady's displacement is 15 meters to the right of where he started, and the total distance he covered is :

Distance = 5m + 25m + 5m + 10m = 45m

5 0

3 years ago

Which TWO correctly relate the attraction between the particles of a liquid and the temperature at which the liquid changes stat

Naddika [18.5K]

A and C because stronger attractions means it needs more energy to break them so a higher temperature is needed

7 0

3 years ago

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The chart show the masses and velocities of two colliding objects that stick together after a collision.

finlep [7]

Answer:

<u><em></em></u>

<u><em>1,500 kg.m/s</em></u>

Explanation:

First, arrange the information in a table:

Object Mass (kg) Velocity (m/s)

A 200 15

B 150 - 10

After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.

According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.

<u>Momentum before the collision, P₁</u>:

$P_1=m_{A,1}\times v_{A,1}+m_{B,1}\times v_{B,1}$

$P_1=200kg\times 15m/s+150kg\times (-10m/s)\\\\ P_1=3000kg.m/s-1500kg.m/s=1500kg.m/s$

<u>Momentum after the collision</u>:

As stated, it es equal to the momentum before the collision: 1,500 kg . m/s

6 0

4 years ago

Two semiconductors are identical except that one has a band gap of 1.2 eV, while the other has a band gap of 1.1 eV. The room te

solong [7]

To solve this problem it is necessary to apply the relationship given by the intrinsic carrier concentration, in each of the phases.

The intrinsic carrier concentration is the number of electrons in the conduction band or the number of holes in the valence band in intrinsic material. This number of carriers depends on the band gap of the material and on the temperature of the material.

In general, this can be written mathematically as

$\eta_i = \sqrt{N_cN_v}e^{-\frac{E_g}{2KT}}$

Both are identical semiconductor but the difference is band gap which is:

$E_{g1} = 1.1eV$

$n_{i1} = 1*10^{19}m^{-3}$

$E_{g2} = 1.2eV$

$T=300K$

The ratio between the two phases are given as:

$\frac{\eta_{i1}}{\eta_{i2}} = \frac{e^{-\frac{E_{g1}}{2KT}}}{e^{-\frac{E_{g2}}{2KT}}}$

$\frac{\eta_{i1}}{\eta_{i2}} = e^{\frac{E_{g2}-E_{g1}}{2KT}}$

$\frac{\eta_{i1}}{\eta_{i2}} =e^{\frac{(1.2-1.1)(1.6*10^{-19})}{2(1.38*10^{-23})(300)}}$

$\frac{\eta_{i1}}{\eta_{i2}} =e^{-1.932367}$

$\frac{\eta_{i1}}{\eta_{i2}} =0.145$

Therefore the ratio of intrinsic carrier densities for the two materials at room temperature is 0.145

7 0

4 years ago