Question

A 13-N weight and a 12-N weight are connected by a massless string over a massless, frictionless pulley. The 13-N weight has a downward acceleration with magnitude equal to that of a freely falling body times:
A. 1
B. 1/12
C. 1/13
D. 1/25
E. 13/25

Answer 1

Answer:

D

Explanation:

We are given that

Weight,$w_1=13 N$

$w_2=12 N$

We have to find the acceleration of 13 N weight .

$m_1=\frac{w_1}{g}=\frac{13}{g}$kg

$m_2=\frac{w_2}{g}=\frac{12}{g} kg$

Net force,$w_1-w_2=13-12=1 N$

Total mass,$m=m_1+m_2=\frac{13}{g}+\frac{12}{g}=\frac{25}{g}$kg

Acceleration,$a=\frac{Net\;force}{total\;mass}$

Using the formula

$a=\frac{1}{\frac{25}{g}}=\frac{1}{25}g$

Where g=Acceleration due to gravity

Hence, option D is true.