" This manual applies to Compact Liquid <span>Fuel Pumps & </span>Dispensers<span> The </span>liquid pressure<span> range is from 0.5 - 20m These totals </span>can<span> be displayed by </span>pressing<span> the CLEAR </span>button<span> on the preset keypad five times in When connecting to sites </span>powered<span> by. "</span>
Answer:
200metters
Explanation:
because in one second hes going 10 metter in 20 second he will go 20×10=200
Explanation:
Assuming the wall is frictionless, there are four forces acting on the ladder.
Weight pulling down at the center of the ladder (mg).
Reaction force pushing to the left at the wall (Rw).
Reaction force pushing up at the foot of the ladder (Rf).
Friction force pushing to the right at the foot of the ladder (Ff).
(a) Calculate the reaction force at the wall.
Take the sum of the moments about the foot of the ladder.
∑τ = Iα
Rw (3.0 sin 60°) − mg (1.5 cos 60°) = 0
Rw (3.0 sin 60°) = mg (1.5 cos 60°)
Rw = mg / (2 tan 60°)
Rw = (10 kg) (9.8 m/s²) / (2√3)
Rw = 28 N
(b) State the friction at the foot of the ladder.
Take the sum of the forces in the x direction.
∑F = ma
Ff − Rw = 0
Ff = Rw
Ff = 28 N
(c) State the reaction at the foot of the ladder.
Take the sum of the forces in the y direction.
∑F = ma
Rf − mg = 0
Rf = mg
Rf = 98 N
I think it false. Sorry if i'm wrong.