When someone has stomach, intestinal, liver, etc, they would go see a gastroenterologist.
Explanation:
Hi Linda,
How's it going?
Sorry I haven't been in touch for such a long time but I've had exams so I've been studying every free minute. Anyway, I'd love to hear all your news and I'm hoping we can get together soon to catch up. We just moved to a bigger flat so maybe you can come and visit one weekend?
How's the new job?
Looking forward to hearing from you!
Helga
Explanation:
it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).
Answer:
B. Resting energy expenditure is the same with basal energy expenditure.
Explanation:
Basal Energy Expenditure can be explained as the energy required to execute essential metabolic functions e.g. coordination of enzymatic reactions in the body system.
On the other hand, Resting Energy Expenditure can be simply explained as the amount of energy expended or burnt when the body is resting.
Hence, in the context of definitions, and relating both definitions, it can be argued that Basal energy expenditure is simply the energy needed to execute essential metabolic functions e.g. coordination of enzymatic reactions in the body, with special emphassy on the body being at rest. Thus, in this context, Basal energy can be looked at through the prism of Resting energy expenditure. Consequently, this two definitions can be used interchangeably, with a special emphassy on perspective.
Answer:
25.7 N
44.8 N
Explanation:
Draw a free body diagram of the block. There are three forces: weight force mg pulling down, buoyancy force ρVg pushing up, and normal force N pushing up.
Sum of forces in the y direction:
∑F = ma
N + ρVg − mg = 0
N = mg − ρVg
N = (3.5 kg) (9.8 m/s²) − (1000 kg/m³) (3.5 kg / 4000 kg/m³) (9.8 m/s²)
N = 25.7 N
The water pushes up on the block with a buoyancy force of ρVg. According to Newton's third law, the block pushes back down on the water with an equal force of ρVg.
The other forces are weight force Mg pulling down, and normal force N pushing up.
Sum of forces in the y-direction:
∑F = ma
N − ρVg − Mg = 0
N = Mg + ρVg
N = (1.4 kg + 2.3 kg) (9.8 m/s²) + (1000 kg/m³) (3.5 kg / 4000 kg/m³) (9.8 m/s²)
N = 44.8 N