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3 years ago

6

H20 + C02...................

1 answer:

icang [17]3 years ago

7 0

Answer:

NICE

Explanation:

TOES

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What is the electron configuration of a chlorine ion in a compound of BeCl2?

mestny [16]

The electronic configuration of a chlorine ion in BeCl2 compound is

[2.8.8]^- (answer B)

chlorine atom gain on electron form Be to form chloride ions
chlorine atom has a electronic configuration of 2.8.7 and it gains one electron to form chloride ion with 2.8.8 electronic configuration

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3 years ago

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What can be dissolve by water

yanalaym [24]

C. All of them can be dissolved because, they are all solvents.

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4 years ago

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Phosphoric acid, which is commonly used as rust inhibitor, food additive and etching agent for dental and orthopedic use, can be

Sphinxa [80]

Answer:

$P_4_{(I)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}$

Explanation:

The first step is:

$P_4_{(I)}+5O_2_{(g)}\rightarrow 2P_2O_5_{(g)}$

Second step is:

$P_2O_5_{(g)}+3H_2O_{(l)}\rightarrow 2H_3PO_4_{(l)}$

Multiplying second step by 2, and adding both the steps, we get that:

$P_4_{(I)}+5O_2_{(g)}+2P_2O_5_{(g)}+6H_2O_{(l)}\rightarrow 2P_2O_5_{(g)}+4H_3PO_4_{(l)}$

Cancelling common species, we get that:

$P_4_{(l)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}$

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4 years ago

Find the initial temperature of 45.0g of water if its final Temperature after submerging a metal with the mass of 8.5g is 22.0°C

Korolek [52]

The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

<em>"Your question is not complete, it seems to be missing the following information;"</em>

the specific heat capacity of the metal is 0.45 J/g⁰C.

The given parameters;

<em>mass of water, </em> $m_w$ <em> = 45 g</em>
<em>final temperature of the water, </em> $t_w$ <em> = 22 ⁰C</em>
<em>mass of the metal, m = 8.5 g</em>
<em>initial temperature of the metal, t = 82 ⁰C.</em>
<em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>

The initial temperature of the water will be calculated by applying the principle of conservation of energy;

<em>heat gained by water = heat lost by metal</em>

$Q_{water} = Q_{metal}$

$m_wc_w \Delta t_w = mc\Delta t$

where;

$c_w$ <em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>

<em />

<em>Substitute the given values;</em>

45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)

4142.16 - 188.28t = 240.98

188.28t = 4142.16 - 240.98

188.28t = 3901.18

$t = \frac{3901.18}{188.28} \\\\t = 20.7 \ ^0 C$

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.

Learn more here:brainly.com/question/15345295

8 0

3 years ago

just help me with 2a) but if you have a lot of time you can just give me answer for all of it so i can check my answer , thank y

stepladder [879]

Answer:

The reaction forming aluminum bromide is Al + 3Br2 → 2AlBr3

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