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kumpel [21]
2 years ago
8

Calculate the energy E of a sample of 3.50 mol of ideal oxygen gas (O2) molecules at a temperature of 310 K. Assume that the mol

ecules are free to rotate and move in three dimensions, but ignore vibrations.
Chemistry
1 answer:
love history [14]2 years ago
7 0

Answer:

13.53 kJ

Explanation:

The energy of a gas can be calculated by the equation:

E = (3/2)*n*R*T

Where n is the number of moles, R is the gas constant (8.314 J/mol.K), and T is the temperature.

E = (3/2)*3.5*8.314*310

E = 13,531.035 J

E = 13.53 kJ

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What is the answer to this:
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The sun has been up for several hours, and it has been shining on these trees. What can the trees do because they are in sunligh
Nonamiya [84]

Answer:

1. C. take in carbon from the air. The carbon is used to make energy storage

molecules.

2. b Carbon is moving into the air and out of the air at the same time

Explanation:

Question 1:

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8 0
3 years ago
The chemical equation for a reaction between K2Cr2O7 and HCl is shown.
deff fn [24]

K2Cr2O7 + 14HCl → 2CrCl3 + 2KCl + 3Cl2 + 7H2O

the correct option is :

K2Cr2O7, because the oxidation number of Cr changes from +6 to +3.


<u>Oxidation number of Cr in K2Cr2O7 is:</u>

K2Cr2O7 = 2K + 2 Cr + 7 O

= 2(+1) + 2Cr + 7(-2)

= 2 + 2Cr -14

[total charge on K2Cr2O7 = 0], Hence;

2 + 2Cr -14 = 0

2Cr -12 = 0

2Cr = 12

Cr = 12/2

<u>Cr = +6</u>


<u>Oxidation number of Cr in CrCl3 is:</u>

CrCl3 = Cr + 3Cl = 0

Cr + 3(-1) = 0

Cr -3 = 0

<u>Cr = +3</u>

Hence Cr is changing its oxidation number from

+6 in K2Cr2O7 to +3 in CrCl3.

Since the oxidation number of Cr [ +6 → +3] is decreasing here,

Cr is getting reduced.

 

so K2Cr2O7 is an oxidizing agent,as it is getting itself reduced and oxidizes others.

3 0
3 years ago
Read 2 more answers
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