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Jet001 [13]
3 years ago
13

How do you write a rule for determining possible values of a variable in an inequality????

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0
Solving'' an inequality<span> means </span>finding<span> all of its solutions. A "solution'' of an </span>inequality<span> is a number which when substituted for the </span>variable<span> makes the </span>inequality<span> a true statement. ... </span>Rule<span> 3b. Multiplying/dividing by the same NEGATIVE number on both sides AND changing the ... All real </span>numbers<span> less than 1 solve the </span>inequality<span>.</span>
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PLEASE HELP!! WILL GIVE BRAINIEST!!​
muminat

Answer:

1) c (a,b)

2)The length of DB (I can't put the line on top)

3) AC

4 0
3 years ago
15 of 20 answer
expeople1 [14]

Answer:

8 bags

Step-by-step explanation:

You divided them by 20 which gives you 4. So you take the 3 and multiply by 4 which is 12 bags. And then you do the same for your bags which makes you do 2 times 4 which gives you 8. You take 20 - 12 and that leaves you with 8.

3 0
3 years ago
Please please answer my question please answer my question
Luda [366]

Answer:

A. Convex heptagon Is the correct answer

Step-by-step explanation:

Please mark brainliest!

4 0
3 years ago
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Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer
almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

\to \mu=\frac{\sum xi}{n}

       =22.8

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187

In point b:

\to \mu=\frac{\sum xi}{n}

       =20.6875  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251

In point c:

 \to \mu=\frac{\sum xi}{n}

         =21  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179

In point d:

\to \mu=\frac{\sum xi}{n}

       =20.8375  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\  =\sqrt{0.553166667} \\\\ =0.7438

6 0
3 years ago
What is the coefficient in this expression? <br> 17 + 5a
babymother [125]
The answer is the a next to the 5
4 0
3 years ago
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