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Jet001 [13]
3 years ago
13

How do you write a rule for determining possible values of a variable in an inequality????

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0
Solving'' an inequality<span> means </span>finding<span> all of its solutions. A "solution'' of an </span>inequality<span> is a number which when substituted for the </span>variable<span> makes the </span>inequality<span> a true statement. ... </span>Rule<span> 3b. Multiplying/dividing by the same NEGATIVE number on both sides AND changing the ... All real </span>numbers<span> less than 1 solve the </span>inequality<span>.</span>
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The members of the basketball team ordered 5 tuna sandwiches at $3.99 each, 5 fish tacos at $2.75 each, 3 salads at $2.70 each,
Oliga [24]

Firstly, $3.99 × 5 = $19.95

Second, $2.75 × 5 = $13.75

Third, $2.70 × 3 = $8.1 (Since it is just $8.1 that won't make sense so we'd add a 0 so It's $8.10.)

Then we do the last one which is 13 × $0.89 = $11.57.

So now since we are done multiplying we can add it all up.

The answer is $53.37 when we finish adding it up.

and I don't know what A number sentence is sorry :(

I took a long time typing this :< I hope this helps though! :D

7 0
3 years ago
Which stands for 250 feet below sea level?
Lubov Fominskaja [6]
-250 feet, because you are 250 feet below sea level.
3 0
3 years ago
Read 2 more answers
Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)
Fantom [35]

Answer:

Given: \sin(x) = (4/5).

Assuming that 0 < x < 90^{\circ}, \cos(x) = (3/5) while \tan(x) = (4/3).

Step-by-step explanation:

By the Pythagorean identity \sin^{2}(x) + \cos^{2}(x) = 1.

Assuming that 0 < x < 90^{\circ}, 0 < \cos(x) < 1.

Rearrange the Pythagorean identity to find an expression for \cos(x).

\cos^{2}(x) = 1 - \sin^{2}(x).

Given that 0 < \cos(x) < 1:

\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}.

Hence, \tan(x) would be:

\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}.

7 0
2 years ago
N ∆ABC, if sin A = and tan A = , then what is cos A?
leva [86]

Answer:hello :

tanA = sinA/cosA

cosA = sinA /tanA

cosA =(4/5)/(4/3)

cosA=3/5

Step-by-step explanation:

8 0
3 years ago
Answer please I need the help lol so as soon as possible will be great! Thanks!
Vikentia [17]

Answer:

pretty sure it's irrational numbers

6 0
3 years ago
Read 2 more answers
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