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SSSSS [86.1K]
2 years ago
14

One app named meet here is the link of that come here with the linkstnjgsozbq​

Chemistry
1 answer:
hoa [83]2 years ago
5 0

Answer:

https://www.meetmehere.com/

this??

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A solution...
steposvetlana [31]

Answer:

A

Explanation:

8 0
3 years ago
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How can the prevailing winds be different during an El Nino year?
ad-work [718]

Answer: During an El Nino year, weakening winds along the equator lead to warming water surface temperatures that lead to further weakening of the winds

3 0
3 years ago
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What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?​
tatiyna

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

6 0
3 years ago
Use the law of conservation of mass to answer the questions.
irinina [24]

Answer:

\boxed {\boxed {\sf 28 \ grams}}

Explanation:

The Law of Conservation of Mass states that mass cannot be created or destroyed.

In terms of a chemical reaction, the mass of the reactants has to equal the mass of the products.

The reactants are A and B. The mass of A is 19 grams and the mass of B is 24 grams. Add the masses.

  • 19 g + 24 g= 43 g

This is the mass of the reactants.

The products and C and D. The mass of C is 15 grams. The mass of the products has to equal the mass of the reactants, which is 43 grams. Subtract 15 from 43 to find D's mass.

  • 43 g - 15 g= 28 g

<u>28 grams</u> of D will be produced.

5 0
3 years ago
the solubility product Ag3PO4 is: Ksp = 2.8 x 10^-18. What is the solubility of Ag3PO4 in water, in moles per liter?
guapka [62]

Answer : The solubility of Ag_3PO_4 in water is, 1.8\times 10^{-5}mol/L

Explanation :

The solubility equilibrium reaction will be:

Ag_3PO_4\rightleftharpoons 3Ag^++PO_4^{3-}

Let the molar solubility be 's'.

The expression for solubility constant for this reaction will be,

K_{sp}=[Ag^{+}]^3[PO_4^{3-}]

K_{sp}=(3s)^3\times (s)

K_{sp}=27s^4

Given:

K_{sp} = 2.8\times 10^{-18}

Now put all the given values in the above expression, we get:

K_{sp}=27s^4

2.8\times 10^{-18}=27s^4

s=1.8\times 10^{-5}M=1.8\times 10^{-5}mol/L

Therefore, the solubility of Ag_3PO_4 in water is, 1.8\times 10^{-5}mol/L

3 0
3 years ago
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