Answer:
CH₄ - 162 ⁸C
CH₃CH₃ -88.5 ⁸C
(CH₃)₂ CHCH₂CH₃ 28 ⁸C
CH₃3(CH2)₃CH₃ 36 ⁸C
CH₃OH 64.5 ⁸C
CH₃CH₂OH 78.3 ⁸C
CH₃CHOHCH₃ 82.5 ⁸C
C₅H₉OH 140 ⁸C
C₆H₅CH₂OH 205 ⁸C
HOCH₂CHOHCH₂OH 290 ⁸C
Explanation:
To answer this question we need first to understand that for organic compounds:
a. Non polar compounds have lower boiling points than polar ones of similar structure and molecular weight.
b. Boiling points increase with molecular weight. In alkane compounds if we compare isomers, the straight chain isomer will have a higher boiling point than the branched one (s) because of London dispersion intermolecular forces.
a. The introduction of hydroxyl groups increase the intermolecular forces and hence the boiling points because the electronegative oxygen, and, more importantly the presence of hydrogen bonds.
Considering the observations above, we can match the boiling points as follows:
CH₄ - 162 ⁸C
CH₃CH₃ -88.5 ⁸C
(CH₃)₂ CHCH₂CH₃ 28 ⁸C
CH₃3(CH2)₃CH₃ 36 ⁸C
CH₃OH 64.5 ⁸C
CH₃CH₂OH 78.3 ⁸C
CH₃CHOHCH₃ 82.5 ⁸C
C₅H₉OH 140 ⁸C
C₆H₅CH₂OH 205 ⁸C
HOCH₂CHOHCH₂OH 290 ⁸C
Note: There was a mistake in the symbols used for the 162 and 88.5 values which are negative and correspond to the common gases methane and ethane
Answer:
Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure
Explanation:
The configuration of these elements is as follows;
Cl₁₇ = 2, 8,7 (the outer electron is 7)
Ca₂₀ = 2,8,8,2 (the outer electron is 2)
Ne₁₀ = 2,8 (the outer electron is 8)
Na₁₁ = 2,8,1 (the outer electron is 1)
Based on the outer electron value above, Neon (Ne) has the most stable outer electron configuration because the outer electron is completely filled and it has octet structure.
It’s A because bleach doesn’t sting on touch and you can’t taste it
