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zimovet [89]
3 years ago
7

according to the balanced chemical equation below,how many grams of h20 are produced if 3.98g of co2 were produced. 2C18H18 + 25

O2= 16Co2 + 18h20.​

Chemistry
1 answer:
telo118 [61]3 years ago
3 0

Answer:

Primero debes usar los gramos de co2 y luego buscar su peso molecular, luego de eso usar la relación de moles entre CO2 y H2O y por último buscar el pm del H2O pata ver cuantos gramos de produce.

Explanation:

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Identify any solutes and solvents present in a mixture of 0.05 mol ethanol, 1 liter water, and 0.2 g hydrogen
Varvara68 [4.7K]

Answer:

Water is the solvent

Both the ethanol and the hydrogen peroxide are the solute

Explanation:

Both the hydrogen peroxide and ethanol are sisobable in water.

There are 0.05 moles of ethanol.

1 litreof water contains 55.55 moles of water.

0.2 g of hydrogen peroxide contains 0.2/34 = 0.0059 moles of hydrogen peroxide (the 34 is the molar mass of hydrogen peroxide).

Since there are more moles of water, water becomes the solvent and the other two liquids dissolve in it.

6 0
3 years ago
What is the temperature of 0.460 mol of gas at a pressure of 1.2 atm and a volume of 12.5 L ? Express your answer using two sign
Taya2010 [7]

The temperature is 370K.

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Density is immediately proportional to stress and indirectly proportional to temperature. As stress increases, with temperature constant, density will increase. Conversely when temperature increases, with strain regular, density decreases.

The equations describing those legal guidelines are unique cases of the best gasoline regulation, PV = NRT, wherein P is the pressure of the gas, V is its extent, n is the number of moles of the gas, T is its kelvin temperature, and R is the ideal (common) gas constant.

Learn more about pressure here: brainly.com/question/25736513

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5 0
2 years ago
Please help me asap ​
stiks02 [169]

Answer:

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5 0
3 years ago
Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How m
nlexa [21]

Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

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Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, <em>W = -80 atm×L ≡ -8,1 kJ</em>

This is the work done in expansion of the gas.  As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

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4 years ago
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