Answer:
The final volume is 3.07L
Explanation:
The general gas law will be used:
P1V1 /T1 = P2V2 /T2
V2 =P1 V1 T2 / P2 T1
Give the variables to the standard unit:
P1 = 345 torr = 345 /760 atm = 0.4539atm
T1 = -15°C = -15 + 273 = 258K
V1 = 3.48L
T2 = 36°C = 36+ 273 = 309K
P2 = 468 torr = 468 * 1/ 760 atm = 0.6158atm
V2 = ?
Equate the values into the gas equation, you have:
V2 = 0.4539 * 3.48 * 309 / 0.6158 * 258
V2 = 488.0877 /158.8764
V2 = 3.07
The final volume is 3.07L
For Row 1 according to the respective Column is
- Zn^{2+} , 32 ,65 ,32 ,30 ,34 ,2+
For Row 2 according to the respective Column is
- Mn, 25, 55, 25, 25,30, 3-
For Row 3 according to the respective Column is
For Row 4 according to the respective Column is
- O^{2-} , 8 ,16 ,8 ,6 ,8 , 2-
For Row 5 according to the respective Column is
- Na, 11, 23, 11, 10, 12, 1-
From the question we are told
Ions, isotope, average atomic mass fill in the blank
Generally
Where
- Z signifies the Proton Number of the atom
- A signifies Mass Number of the atom
Therefore
For Row 1 according to the respective Column is
- Zn^{2+} , 32 ,65 ,32 ,30 ,34 ,2+
For Row 2 according to the respective Column is
- Mn, 25, 55, 25, 25,30, 3-
For Row 3 according to the respective Column is
For Row 4 according to the respective Column is
- O^{2-} , 8 ,16 ,8 ,6 ,8 , 2-
For Row 5 according to the respective Column is
- Na, 11, 23, 11, 10, 12, 1-
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<u>Switch the 3 and the 4</u>, this change must made to the coefficients to balance this equation.
Now, the correct balance equation is C₃H₈ + 5 O₂ → 3 CO₂ + 4H₂O
This method of balancing chemical equations involves assigning algebraic variables as stoichiometric coefficients to each species in the unbalanced chemical equation.
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According to the PH formula:
PH= Pka +㏒ [strong base/weak acid]
when we have PH at the first equivalence =3.35 and the Pka1 = 1.4
So, by substitution, we can get the value of ㏒[strong base / weak acid]
3.35 = 1.4 + ㏒[strong base/ weak acid]
∴㏒[strong base/weak acid] = 3.35-1.4 = 1.95
to get the Pka2 we will substitute with the value of ㏒[strong base/ weak acid] and the value of PH of the second equivalence point
∴Pk2 = PH2 - ㏒[strong base/ weak acid]
= 7.55 - 1.95 = 5.6
