Answer:
(a) The resistance R of the inductor is 2480.62 Ω
(b) The inductance L of the inductor is 1.67 H
Explanation:
Given;
emf of the battery, V = 16.0 V
current at 0.940 ms = 4.86 mA
after a long time, the current becomes 6.45 mA = maximum current
Part (a) The resistance R of the inductor

Part (b) the inductance L of the inductor

where;
L is the inductance
R is the resistance of the inductor
t is time

Therefore, the inductance is 1.67 H
i would say, are sour and corrode metals
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