In a sine curve, like a water wave, the high points are the crests and the low points are the (blank)

calculate how much charge passes through the LED in 1 hour if the current flowing in the circuit below is 350mA

Morgarella [4.7K]

Given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

<h3>What is Current?</h3>

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = Q/t

Where Q is the charge and t is time elapsed.

Given the data in the question;

Time elapsed t = 1hr = 3600s

Current I = 350mA = 0.35A

Charge Q = ?

We substitute our given values into the expression above to determine the charge.

I = Q/t

Q = I × t

Q = 0.35A × 3600s

Q = 1260C

Therefore, given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

Learn more about current here: brainly.com/question/3192435

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3 0

2 years ago

Two point charges of +20.0 μC and -8.00 μC are separated by a distance of 20.0 cm. What is the intensity of electric field E mid

algol13

Answer:

The intensity of the net electric field will:

$E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C$

Explanation:

Here we need first find the electric field due to the first charge at the midway point.

The electric field equation is given by:

$|E_{1}|=k\frac{q_{1}}{d^{2}}$

Where:

k is Coulomb's constant
q(1) is 20.00 μC or 20*10⁻⁶ C
d is the distance from q1 to the midpoint (d=10.0 cm)

So, we will have:

$|E_{1}|=(9*10^{9})\frac{20*10^{-6}}{0.1^{2}}$

$|E_{1}|=1.8*10^{7}\: N/C$

The direction of E1 is to the right of the midpoint.

Now, the second electric field is:

$|E_{2}|=k\frac{q_{2}}{d^{2}}$

$|E_{2}|=(9*10^{9})\frac{8*10^{-6}}{0.1^{2}}$

$|E_{2}|=7.2*10^{6}\: N/C$

The direction of E2 is to the right of the midpoint because the second charge is negative.

Finally, the intensity of the net electric field will:

$E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C$

I hope it helps you!

5 0

3 years ago

A train travels 70 kilometers in 1 hours, and then 63 kilometers in 2 hours. What is its average speed?

lozanna [386]

The answer is: " 44 $\frac{1}{3}$ km " ;
or; write as: " 44.333 km " .
___________________________________________________________
Explanation:
___________________________________________________________
(70 km + 63 km) ÷ (2 + 1 ) = 133 km ÷ 3 = " 44 $\frac{1}{3}$ km " ;
or; write as: " 44.333 km " .
___________________________________________________________

3 0

4 years ago

The layer of the Earth that is composed of large plates that interlock and move over time is the _______. asthenosphere lithosph

siniylev [52]

The lithosphere because it includes the outer region of the earth including the crust and outer mantle

4 0

3 years ago

Read 2 more answers

Please help! Giving 20 points!!

MrMuchimi

Answer:

Explanation:

Remark

This is a momentum question. Both cars are sitting still (v1 and v2 are both 0) to start with). When the spring is sprung), they both move but in opposite directions.

Let us say that v4 is minus.

Equation

0 = m3*v3 - m4* v4

Givens

m3 = 1750 kg

m4 = 1000 kg

v3 = 4 m/s

Solution

m3*4m/s - m4*x = 0

1750 * 4 - 1000*x = 0

1750 * 4 = 1000x

7000 = 1000 x

7000/1000 = x

x = 7 m/s

7 0

3 years ago