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4 years ago

What is in fire works

1 answer:

7 0

Traditionally, gunpowder used in fireworks was made of 75 percent potassium nitrate also called saltpeter mixed with 15 percent charcoal and 10 percent sulfur; modern fireworks sometimes use other mixtures (such as sulfurless powder with extra potassium nitrate) or other chemicals instead

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The decomposition of hydrogen peroxide was studied, and the following data were obtained at a particular temperature: Time (s) (

harina [27]

Answer:

Part a: The rate of the equation for 1st order reaction is given as $Rate=k[H_2O_2]$

Part b: The integrated Rate Law is given as $[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c: The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d: Concentration after 4000 s is 0.043 M.

Explanation:

By plotting the relation between the natural log of concentration of $H_2O_2$ , the graph forms a straight line as indicated in the figure attached. This indicates that the reaction is of 1st order.

Part a

Rate Law

The rate of the equation for 1st order reaction is given as

$Rate=k[H_2O_2]$

Part b

Integrated Rate Law

The integrated Rate Law is given as

$[H_2O_2]=[H_2O_2]_0 e^{-kt}$

Part c

Value of the Rate Constant

Value of the rate constant is given by using the relation between 1st two observations i.e.

t1=0, M1=1.00

t2=120 s , M2=0.91

So k is calculated as

$-k(t_2-t_1)=ln{\frac{M_2}{M_1}}\\-k(120-0)=ln{\frac{0.91}{1.00}}\\k=\frac{-0.09431}{-120}\\k=7.8592 \times 10^{-4} s^{-1}$

The value of rate constant is $7.8592 \times 10^{-4} s^{-1}$

Part d

Concentration after 4000 s is given as

$-k(t_2-t_1)=ln{\frac{M_2}{1.0}}\\-7.8592 \times 10^{-4}(4000-0)=ln{\frac{M_2}{1.00}}\\-3.1437=ln{\frac{M_2}{1.00}}\\M_2=e^{-3.1437}\\M_2=0.043 M$

Concentration after 4000 s is 0.043 M.

7 0

3 years ago

Name two "Storage Polysaccharides" and two "Structural Polysaccharides"

Vsevolod [243]

Answer:

Examples of storage polysaccharides - starch and glycogen and structural polysaccharides - cellulose and chitin

Explanation:

Polysaccharides are the complex carbohydrate polymers, composed of monosaccharide units that are joined together by glycosidic bond.

In other words, polysaccharides are the carbohydrate molecules that give monosaccharides or oligosaccharides on hydrolysis.

The examples of storage polysaccharides are starch and glycogen. The examples of structural polysaccharides are cellulose and chitin.

6 0

3 years ago

Which of the following is improper isotope notation? Explanation: Nineteen is potassium's atomic number

sasho [114]

Answer:

C. Potassium-19 .

Explanation:

Hello!

In this case, since isotopes are known be atoms of the same element with equal atomic number but different mass number, we can consider the case of carbon which has two natural occurring ones, carbon-12 and carbon-13 whereas carbon-12 has the greatest abundance. However, isotope notation may take two forms:

1. Symbol of the element followed by a dash indicating the mass number of the isotope, for instance: C-12, K-39, and so on.

2. Name of the element followed by a dash indicating the mass number of the isotope, for instance: Carbon-12, Potassium-39, and so on.

In such a way, the improper isotope notation is C. Potassium-19 , considering that A should be K-39 because atomic symbol of potassium is K, not k.

Best regards!

7 0

3 years ago

Which term defines the amount that a solute can dissolve into a solution?

Readme [11.4K]

The correct answer for the question that is being presented above is this one: "C. solubility level." The term defines the amount that a solute can dissolve into a solution is called the solubility level. The higher the solubility level, the faster it dissolves.

6 0

3 years ago

A particular experiment requires 13.5 µl hydrochloric acid solution. if 250 ml hydrochloric acid solution is available, how many

ladessa [460]

The amount of HCl required for one experiment - 13.5 µl
the volume in terms of L - 13.5 x 10⁻⁶ L
the volume of HCl available - 0.250 L
since one experiment uses up - 13.5 x 10⁻⁶ L
then number of experiments - 0.250 L / 13.5 x 10⁻⁶ L = 1.8 x 10⁴ times
the experiment can be carried out 18000 times

6 0

3 years ago

Read 2 more answers