Question

Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the result

Answer 1

Answer: 0.3872m

Explanation:

q= 100nC -->  100x10^-9 C

k= 9x10^9 Nm^2/C^2

E= 6kN/C --> 600 N/C

r=?

$E= K\frac{q}{r^{2} }$ --> $r=\sqrt{\frac{kq}{E} }$ Despejas "r"

Resuelves

$r=\sqrt{\frac{(9x10^9 Nm^2/C^2)(100x10x^{-9} C)}{6000N/C} }$  (la x es por, no es una variable)

r= 0.3872983346m