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Alexandra [31]
3 years ago
14

Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the r

esult
Physics
1 answer:
madam [21]3 years ago
4 0

Answer: 0.3872m

Explanation:

q= 100nC -->  100x10^-9 C

k= 9x10^9 Nm^2/C^2

E= 6kN/C --> 600 N/C

r=?

E= K\frac{q}{r^{2} } --> r=\sqrt{\frac{kq}{E} } Despejas "r"

Resuelves

<h3>r=\sqrt{\frac{(9x10^9 Nm^2/C^2)(100x10x^{-9}  C)}{6000N/C} }  (la x es por, no es una variable)</h3><h3>r= 0.3872983346m</h3>
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