The given terms are :
Current = 0.8 Amperes
Time = 3 minutes = 3 × 60 = 180 seconds
we know that,
now, let's solve for charge (q) :
Total Charge (q) = 144 Coulombs
Find the distance from a point charge q=100nC where the field intensity is equal to E=6kN/C. please include description of the r
1 answer:
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Answer:
s = 1.7 m
Explanation:
from the question we are given the following:
Mass of package (m) = 5 kg
mass of the asteriod (M) = 7.6 x 10^{20} kg
radius = 8 x 10^5 m
velocity of package (v) = 170 m/s
spring constant (k) = 2.8 N/m
compression (s) = ?
Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore
• Ei = Ef
• Ei = energy in the spring + gravitational potential energy of the system
• Ei = \frac{1}{2}ks^{2} + \frac{GMm}{r}
• Ef = kinetic energy of the object
• Ef = \frac{1}{2}mv^{2}
• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}
• s =
s =
s = 1.7 m
Answer
given,
distance between A and B is equal to 5 m
let x be the distance of loud speaker from the source A
For constructive interference, path difference = mλ
x - (5 - x ) = 0 , for m = 0
2 x - 5 = 0
2 x = 5
x = 2.5 cm
For destructive interference
m = 0
x = 4 , 1 cm