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Tcecarenko [31]
3 years ago
10

You are trying to tune the fifth string on your guitar, which is supposed to sound the A2 note (i.e., a note two octaves below A

4). If the part of your guitar string in between where it is held down is 1.2 m and it has a mass of 0.006 kg, how much tension should you put the string under to get the right tuning?
Physics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

The value is  T =  288 \ N

Explanation:

From the question we are told that

    The length of the guitar string considered is  L = 1.2 \ m

     The mass is m = 0.006 \ kg

Generally the tension is mathematically represented as

       T = 4f ^2 m* L

Here f is the frequency of the A_2 note which is  f= 110 \ Hz

So

     T = 4* 110 ^2 * 0.006* 1.2

=>  T =  288 \ N

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On a tiny scale, what happens to an initially neutral object’s mass when it gains a net positive charge through the exchange of electrons? (<em>the mass will decrease by a very small factor</em>)

(b) What happens to the mass of an initially neutral object when it gains a net negative charge through the exchange of electrons?  (<em>The mass will increase by a very small factor</em>)

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(a) On a tiny scale, what happens to an initially neutral object’s mass when it gains a net positive charge through the exchange of electrons? (<em>the mass will decrease by a very small factor</em>)

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