The cell belongs to the then musculoskeletal system of the body.
<h3>What type of cells contains filaments that can cause the cell to contract, shortening the length of the cell?</h3>
The myocytes or muscle cells are special cells found in smooth, cardiac, and skeletal muscles that have differentiated for the specialized function of contraction.
Myocytes are long, cylindrical, multi-nucleated, and striated. They contain filaments that can cause the cell to contract, shortening the length of the cell.
Skeletal muscle cells contain many mitochondria required to generate sufficient ATP since skeletal muscle cells have high energy requirements.
The muscle cells form a part of the musculoskeletal system of the body.
In conclusion, muscle cells are required for muscular contraction.
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Answer:
The bike would have more acceleration
Explanation:
Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.
Eg.
F=50N
Motorbike M=200kg
F=ma
50=200 x a
50/200=a
0.25m/s/s =a
Bike M=35kg
F=ma
50=35 x a
50/35= a
1.43m/s/s=a
(a) The velocity (in m/s) of the rock after 1 second is 11.28 m/s.
(b) The velocity of the rock after 2 seconds is 7.56 m/s.
(c) The time for the block to hit the surface is 4.03.
(d) The velocity of the block at the maximum height is 0.
<h3>
Velocity of the rock</h3>
The velocity of the rock is determined as shown below;
Height of the rock after 1 second; H(t) = 15(1) - 1.86(1)² = 13.14 m
v² = u² - 2gh
where;
- g is acceleration due to gravity in mars = 3.72 m/s²
v² = (15)² - 2(3.72)(13.14)
v² = 127.23
v = √127.23
v = 11.28 m/s
<h3>Velocity of the rock when t = 2 second</h3>
v = dh/dt
v = 15 - 3.72t
v(2) = 15 - 3.72(2)
v(2) = 7.56 m/s
<h3>Time for the rock to reach maximum height</h3>
dh/dt = 0
15 - 3.72t = 0
t = 4.03 s
<h3>Velocity of the rock when it hits the surface</h3>
v = u - gt
v = 15 - 3.72(4.03)
v = 0
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Answer:
1500 mph
Explanation:
Take east to be +x and north to be +y.
The x component of the velocity is:
vₓ = 889 cos 0° + 830 cos 59°
vₓ = 1316.5 mph
The y component of the velocity is:
vᵧ = 889 sin 0° + 830 sin 59°
vᵧ = 711.4 mph
The speed is found with Pythagorean theorem:
v² = vₓ² + vᵧ²
v² = (1316.5 mph)² + (711.4 mph)²
v = 1496 mph
Rounded to two significant figures, the jet's speed relative to the ground is 1500 mph.