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Tcecarenko [31]
3 years ago
10

You are trying to tune the fifth string on your guitar, which is supposed to sound the A2 note (i.e., a note two octaves below A

4). If the part of your guitar string in between where it is held down is 1.2 m and it has a mass of 0.006 kg, how much tension should you put the string under to get the right tuning?
Physics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

The value is  T =  288 \ N

Explanation:

From the question we are told that

    The length of the guitar string considered is  L = 1.2 \ m

     The mass is m = 0.006 \ kg

Generally the tension is mathematically represented as

       T = 4f ^2 m* L

Here f is the frequency of the A_2 note which is  f= 110 \ Hz

So

     T = 4* 110 ^2 * 0.006* 1.2

=>  T =  288 \ N

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The range of potential energies of the wire-field system for different orientations of the circle are -

θ                  U

0°             375 π x 10^{-7}

90°              0

180°        - 375 π x 10^{-7}

We have current carrying wire in a form of a circle placed in a uniform magnetic field.

We have to the range of potential energies of the wire-field system for different orientations of the circle.

<h3>What is the formula to calculate the Magnetic Potential Energy?</h3>

The formula to calculate the magnetic potential energy is -

U = M.B = MB cos $\theta

where -

M is the Dipole Moment.

B is the Magnetic Field Intensity.

According to the question, we have -

U = M.B = MB cos $\theta

We can write M = IA (I is current and A is cross sectional Area)

U = IAB cos $\theta

U = Iπr^{2}B cos $\theta

For $\theta = 0° →

U(Max) = MB cos(0) = MB =  Iπr^{2}B = 5 × π × ( 0.05 ) ^{2} × 3 × 10^{-3} =

375 π x 10^{-7}.

For $\theta = 90° →

U = MB cos (90) = 0

For $\theta = 180° →

U(Min) = MB cos(0) = - MB =  - Iπr^{2}B = - 5 × π × ( 0.05 ) ^{2} × 3 × 10^{-3} =

- 375 π x 10^{-7}.

Hence, the range of potential energies of the wire-field system for different orientations of the circle are -

θ                  U

0°             375 π x 10^{-7}

90°              0

180°        - 375 π x 10^{-7}

To solve more questions on Magnetic potential energy, visit the link below-

brainly.com/question/13708277

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Answer:

A. These vibrations can travel through solids, liquids, and gases, but not through <u>empty</u><u> </u><u>space</u>.

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Suppose you have a Frisbee with a mass of 0.10 kg. You first throw it with a force of 5N and then change the force you throw it
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Answer:

The acceleration increases.

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Read 2 more answers
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