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3 years ago

How are the solutions to the inequality -2x ≥ 10 different from the solutions to -2x > 10?

Mathematics

1 answer:

CaHeK987 [17]3 years ago

4 0

Answer:

First lets find the solutions to each inequality.

-2x $\geq \\$ 10 and -2x>10 (divide both sides by -2 to solve)

x $\leq$ -5 and x<-5

x $\leq$ -5 tell us that x could be -5 or less.

x<-5 tells us that x could be -6 or less.

The first one is less than or equal to which tells you that there is a possibility that the number is shows is could be an answer

Hope this helps ;)

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Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.

dsp73

Answer:

The required sequence is $a_n=20(\frac{1}{2})^{n-1}$ . The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, $a_2=10,a_3=5,a_4=2.5,a_5=1.25$

$r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}$

The common ratio of GP is 1/2.

$r=\frac{a_2}{a_1}$

$\frac{1}{2}=\frac{10}{a_1}$

$a_1=20$

The first term of the sequence is 20.

The formula for sequence is

$a_n=a(r)^{n-1}$

Where a is first term and r is common difference.

The required sequence is

$a_n=20(\frac{1}{2})^{n-1}$

The formula for rate of change is

$m=\frac{f(x_2)-f(x_1)}{x_2-x_1}$

The average rate of change from n = 1 to n = 3 is

$m=\frac{f(3)-f(1)}{3-1}$

$m=\frac{5-20}{3-1}$

$m=\frac{-15}{2}=-7.5$

Therefore the required sequence is $a_n=20(\frac{1}{2})^{n-1}$ . The average rate of change from n = 1 to n = 3 is -7.5.

8 0

3 years ago

Read 2 more answers

Help please will mark brainliest!!!

Daniel [21]

Answer:

45°

Step-by-step explanation:

Well, compared to 90°, it looks like it's just smaller, but not too small. It couldn't be 15° degrees, or 60°, as it was probably too much. I Don't think it's 30° either, because it looked bigger than what a 30° angle would be.

Hope it helped!

~Flip

7 0

2 years ago

What is the counter example of when it rains it pours

Ganezh [65]

A counterexample proves something wrong. To disprove "When it rains, it pours," you could give an example of a time when it rains and does not pour. What if it only rains a little? What if it rains frogs? How are you supposed to "pour" frogs? I dunno. This is sort of an open-ended question. I'd go with "It drizzles, but does not pour."

5 0

2 years ago

Does anybody understand writing equations in slope intercept form?

aleksandr82 [10.1K]

slope intercept form

y=mx+b

where m is the slope and b is the y intercept

if we change from point slope form

y-y1 = m(x-x1)

we distribute

y-y1 = mx -x*x1

then add y1 to each side

y = mx -x*x1+y1

remember x and y are variables and should stay in the equation

m,x1,y1 are numbers from the problem

you may have to calculate the slope (m) from the formula

m = (y2-y1)/(x2-x1) from two points on the line

4 0

2 years ago

Read 2 more answers

Determine whether the relation is a function. -8, 0 -1, 5 4,10,11

11111nata11111 [884]

Vas happenin!

It’s a function because the Xs don’t repeat

Hope this helps

-Zayn Malik

6 0

3 years ago