Answer:
#include <stdio.h>
int main()
{
int threshold = 5;
int i,j;
int matrix[5][5] = {{4, 4, 4, 2, 2},
{4, 2, 2, 2, 2},
{2, 2, 8, 7, 2},
{2, 8, 8, 8, 2},
{8, 2, 2, 2, 8}};
int row=(sizeof(matrix)/sizeof(matrix[0])); // length of row
int column=(sizeof(matrix)/sizeof(matrix[0][0]))/row; // length of column
printf("Input matrix value:\n");
for(i=0; i <5; i++)
{
for(j=0; j<5; j++)
{
printf("%d ", matrix[i][j]);
}
printf("\n");
}
printf("\n");
for(i=0; i<column; i++)
{
for(j=0; j<column; j++)
{
if ( (j == 0) || (j == column-1) ) // print 0 for first and last element of every row
printf("%d ", 0);
else
{
if(matrix[i][j] > threshold) // veify whether the element is more than threshold
{
printf("%d ",1);
}
else
{
printf("%d ", 0);
}
}
}
printf("\n");
}
return 0;
}
Answer:
For Figure Below, if the elevation of the benchmark A is 25.00 m above MSL:
1. Using the Rise and Fall Method, find the reduced level for all points. (Construct the Table)
2. Using HPC Method, find the reduced level for all points. ( Construct the Table).
3. Show all required Arithmetic checks for your work. For Item 1 and 2.
4. What is the difference in height between points H and D?
5. What is the gradient of the line connecting A and J, knowing that horizontal distance = 200
m.
Answer:
modify temperature is lower than by the 0.196 %
Explanation:
given data
D = 250 mm
d = 0.1 mm
v = 0.5 m/s
V = 50 m/s
D = 150 mm
d = 0.1 mm
v = 0.3 m/s
V = 25 m/s
solution
first we get here initial coating condition for temperature change ΔT is
ΔT = A \times D^{1/4} \times d^{3/4}\times \frac{V}{v}^{1/2} ...............1
put here value for both condition
ΔT = A \times 250^{1/4} \times 0.1^{3/4}\times \frac{50}{0.5}^{1/2}
ΔT = 7.07 A ......................2
and
ΔT = A \times 150^{1/4} \times 0.1^{3/4}\times \frac{25}{0.3}^{1/2}
ΔT = 5.68 A .......................3
so here percentage change is
percentage change =
percentage change = - 0.196
so that modify temperature is lower than by the 0.196 %
Answer:
Check the Attached Image
Explanation:
The full solution is in the attached image below
OA bloom is smaller than a bar