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OverLord2011 [107]
3 years ago
14

This scenario shows a 0.1-m diameter pipe at A filling a tank that is 2.0 m long and 1.9 m wide. Water flowing at a constant rat

e fills the tank to a height of 3.8 m in 7 minutes. Determine the average velocity of the flow from the pipe at A. Show your answer to 3 significant figures with units of m/s.
Engineering
1 answer:
charle [14.2K]3 years ago
5 0

Answer:

See explanations

Explanation:

(a) For steady flow we have

Q1 + Q2 + Q3 = Q4, or Fig. P3.8

VA VA VA VA 11 2 2 33 4 4 + + = (1)

Since 0.2Q3 = 0.1Q4, and Q4 = (120 m3/h)(h/3600 s) = 0.0333 m3/s,

3

4

3

2 3

(0.0333 m /s) (b) 2 (0.06 ) 2

Q V Ans.

A π == = 5.89 m/s

Substituting into (1),

22 2

1 (0.04 ) (5) (0.05 ) (5.89) (0.06 ) 0.0333 (a) 44 4

V Ans. ⎛⎞ ⎛⎞ ⎛⎞ ππ π

⎜⎟ ⎜⎟ ⎜⎟ ++ = ⎝⎠ ⎝⎠ ⎝⎠ V 5.45 m/s 1 =

From mass conservation, Q4 = V4A4

3 2

4 (0.0333 m /s) V ( )(0.06 )/4 (c) = π

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A block of ice weighing 20 lb is taken from the freezer where it was stored at -15"F. How many Btu of heat will be required to c
Rus_ich [418]

Answer:

Heat required =7126.58 Btu.

Explanation:

Given that

Mass m=20 lb

We know that

1 lb =0.45 kg

So 20 lb=9 kg

m=9 kg

Ice at -15° F and we have to covert it at 200° F.

First ice will take sensible heat at up to 32 F then it will take latent heat at constant temperature and temperature will remain 32 F.After that it will convert in water and water will take sensible heat and reach at 200 F.

We know that

Specific heat for ice C_p=2.03\ KJ/kg.K

Latent heat for ice H=336 KJ/kg

Specific heat for ice C_p=4.187\ KJ/kg.K

We know that sensible heat given as

Q=mC_p\Delta T

Heat for -15F to 32 F:

Q=mC_p\Delta T

Q=9\times 2.03(32+15) KJ

Q=858.69 KJ

Heat for 32 Fto 200 F:

Q=mC_p\Delta T

Q=9\times 4.187(200-32) KJ

Q=6330.74 KJ

Total heat=858.69 + 336 +6330.74 KJ

Total heat=7525.43 KJ

We know that 1 KJ=0.947 Btu

So   7525.43 KJ=7126.58 Btu

So heat required to covert ice into water is 7126.58 Btu.

8 0
3 years ago
What test should be performed on abrasive wheels
Svet_ta [14]

Answer:

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3 0
3 years ago
Read 2 more answers
a coil consists of 200 turns of copper wire and has a cross-sectional area of 0.8mm square . The mean length per turn is 80 cm a
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8 0
3 years ago
A cylindrical drill with radius 4 is used to bore a hole through the center of a sphere of radius 5. Find the volume of the ring
ANTONII [103]

Answer:

The volume of the ring shaped solid that remains is 21 unit^3.

Explanation:

The total volume of the sphere is given as:

Volume of Sphere = (4/3)πr^3

where, r = radius of sphere

Volume of Sphere = (4/3)(π)(5)^3

Volume of Sphere = 523.6 unit^3

Now, we find the volume of sphere removed by the drill:

Volume removed = (Cross-sectional Area of drill)(Diameter of Sphere)

Volume removed = (πr²)(D)

where, r = radius of drill = 4

D = diameter of sphere = 2*5 = 10

Therefore,

Volume removed = (π)(4)²(10)

Volume removed = 502.6 unit^3

Therefore, the volume of ring shaped solid that remains will be the difference between the total volume of sphere, and the volume removed.

Volume of Ring = Volume of Sphere - Volume removed

Volume of Ring = 523.6 - 502.6

<u>Volume of Ring = 21 unit^3</u>

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For each topic, find the total number of blurts that were analyzed as being related to the topic. Order the result by topic id.
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Answer:

Explanation: see attachment below

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3 years ago
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