QUESTION:

tigry1 [53]

the answer is C cause drivers dont always follow the rules

8 0

3 years ago

Jade wanted to test the effect of ice on the weathering of rocks. She filled two containers with gypsum and placed a water ballo

Aleks [24]

Answer:

The gypsum block with the water balloon has contracted.

Explanation:

7 0

2 years ago

Draw the free-body diagram of the beam which supports the 80-kg load and is supported by the

Sauron [17]

The free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

The first image shows the diagram of the beam and the second image shows the free-body diagram of the beam.

The resolution of forces in the system is well understood by the principle of equilibrium where a stationary body will remain balanced when subject to parallel forces provided that the total sum of the overall external forces is zero.

The free-body diagram is a graphical representation used to visualize the forces applied to an object.

The equilibrium of forces on the x-axis is:

$\mathbf{\sum F_x = 0}$

The equilibrium of forces on the y-axis is:

$\mathbf{\sum F_y = 0}$

The equilibrium condition at any point is:

$\mathbf{\sum M = 0}$

From the free body diagram attached in the second image below,

the horizontal reaction is located at point A as $\mathbf{ A_x}$
the vertical reaction is located at point A as $\mathbf{A_y}$
the tension = T
the weight = W

Therefore, we can conclude that the free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

Learn more about the free-body diagram here:

brainly.com/question/19345060?referrer=searchResults

5 0

2 years ago

A flow of 12 m/s passes through a 6 m wide, 2 m deep rectangular channel with a bed slope of 0. 001. If the mean velocity of flo

prohojiy [21]

Answer:

manning's coefficient is 0.0357

Explanation:

Given:

Velocity of flow, v = 12 m/s

Width of the channel, b = 6 m

Depth of the channel, d = 2 m

bed slope, s = 0.001

mean velocity of flow, V = 1 m/s

now, the velocity is given as:

$V= \frac{1}{n}R^{\frac{2}{3}}S^{\frac{1}{2}}$

where,

n is the manning's coefficient

R is hydraulic mean depth

R = (Area of the channel) / (wetted Perimeter of the channel)

now,

R = (2 × 6) / ((2 × 2) + 6)

or

R = 12 / 10 = 1.2 m

now, on substituting the values in the equation for velocity, we get

$1= \frac{1}{n}1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}$

or

$n= 1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}$

or

n = 0.0357

hence, the value of manning's coefficient is 0.0357

8 0

3 years ago

3. (9 points) A square-thread power screw is used to raise or lower the basketball board in a gym, the weight of which is W = 10

Bezzdna [24]

Answer:

a) 49.95 watts

b) The self locking condition is satisfied

Explanation:

Given data

weight of the square-thread power screw ( w ) = 100 kg = 1000 N

diameter (d) = 20 mm ,

pitch (p) = 2 mm

friction coefficient of steel parts ( f ) = 0.1

Gravity constant ( g ) = 10 N/kg

Rotation of electric power screwdrivers = 300 rpm

A ) Determine the power needed to raise to the basket board

first we have to calculate T

T = Wtan (∝ + Ф ) * $\frac{Dm}{2}$ ------------- equation 1

Dm = d - 0.5 ( 2) = 19mm

Tan ∝ = $\frac{L}{\pi Dm}$ where L = 2*2 = 4

hence ∝ = 3.83⁰

given f = 0.1 , Tan Ф = 0.1. hence Ф = 5.71⁰

insert all the values into equation 1

T = 1.59 Nm

Determine the power needed using this equation

$\frac{2\pi NT }{60}$ = $\frac{2\pi * 300 * 1.59}{60}$

= 49.95 watts

B) checking if the self-locking condition of the power screw is satisfied

Ф > ∝ hence it is self locking condition is satisfied

3 0

2 years ago