Given:
Temperature of water, 
= 
=273 +(-6) =267 K
Temperature surrounding refrigerator, 
= 
=273 + 21 =294 K
Specific heat given for water, 
= 4.19 KJ/kg/K
Specific heat given for ice, 
= 2.1 KJ/kg/K
Latent heat of fusion, 
= 335KJ/kg
Solution:
Coefficient of Performance (COP) for refrigerator is given by:
Max 
= 
= 
= 9.89
Coefficient of Performance (COP) for heat pump is given by:
Max 
= 
= 10.89
Answer:
As a worker, it is important to follow the proper set of instructions or emergency plans during an emergent situation. Not carefully following the rules may result to a bigger problem such as further injury and damage to property.
Explanation:
Evacuation Procedure- This is a step-by-step procedure that people follow in order to safely vacate any building or place. This procedure is applicable to any situation, such as the workplace. This is now called the <em>Workplace Evacuation Procedure. </em>This is very important because there are so many unpredictable situations or events that are happening in the world right now, such as fire or earthquake. This procedure is being done through an evacuation plan.
The awareness of the workers regarding the proper way to evacuate during emergency situation is very important. It will be easier for them to know where to locate the nearest exit route. They will also learn to stop any form of device or equipment that could cause a hazzard during the situation. In case of the hospital, which is also a workplace, the employees will also learn how to assist the patients before themselves. They will also know where to assemble if there's a need to do so.
Answer:
W= 8120 KJ
Explanation:
Given that
Process is isothermal ,it means that temperature of the gas will remain constant.
T₁=T₂ = 400 K
The change in the entropy given ΔS = 20.3 KJ/K
Lets take heat transfer is Q ,then entropy change can be written as
Now by putting the values
Q= 20.3 x 400 KJ
Q= 8120 KJ
The heat transfer ,Q= 8120 KJ
From first law of thermodynamics
Q = ΔU + W
ΔU =Change in the internal energy ,W=Work
Q=Heat transfer
For ideal gas ΔU = m Cv ΔT]
At constant temperature process ,ΔT= 0
That is why ΔU = 0
Q = ΔU + W
Q = 0+ W
Q=W= 8120 KJ
Work ,W= 8120 KJ
Even though the content of many alcohol blends doesn't affect engine driveability, using gasoline with alcohol in warm weather may cause: decrease in fuel economy.
Mark brainliest
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