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kiruha [24]3 years ago

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MaRussiya [10]3 years ago

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Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r

MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0

3 years ago

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A carbon-carbon double bond has a greater bond energy than a carbon-carbon single bond. Because of the greater bond energy, a ca

Ronch [10]

Answer: Carbon-carbon double bond is stronger and shorter than the single bond.

Explanation:

It is given that carbon-carbon double bond has greater energy than the carbon-carbon single bond.

Bond energy is directly proportional to the bond strength, which means that the double bond will have greater strength than single bond and triple bond has the greatest strength of all the bonds.

$\text{Bond energy}\propto \text{Bond strength}$

Bond energy is inversely proportional to the bond length of the carbon-carbon bond. This means that more is the bond energy, shorter will be the bond and vice-versa.

$\text{Bond energy}\propto \frac{1}{\text{Bond Length}}$