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2 years ago

Which formula can be used to calculate the molar mass of hydrogen peroxide (H2O2)? (5 points)

1 answer:

7 0

answer: option d (2×molar mass of H +2×molar mass of O

 

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When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H

Debora [2.8K]

Answer:

$Y=58.15\%$

Explanation:

Hello,

For the given chemical reaction:

$Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)$

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

$n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3$

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

$n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3$

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

$m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3$

Finally, we compute the percent yield with the obtained 2.10 g:

$Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%$

Best regards.

7 0

2 years ago

In humans, genetic material in the cell is organized into

vladimir2022 [97]

23 pairs of chromosomes, since there is 46 singular chromosomes.

6 0

2 years ago

Once again if anyone could help, I would really appreciate your help! Thank you ❤️

Nikolay [14]

Answer:

Explanation:

I explained how to do it on your other problem so look there :)

6 0

3 years ago

stearic acid and linoleic acid stearic acid and linoleic acid stearic acid has the higher melting point, because it has two more

elena55 [62]

Acid palmitic acid has higher melting point, because it has two more methylene groups.

$\text { Myristic acid } \rightarrow \mathrm{CH}_3\left(\mathrm{CH}_2\right)_{12} \mathrm{COOH} \\& \text { Palmitic acid } \rightarrow \mathrm{CH}_3\left(\mathrm{CH}_2\right)_{14} \mathrm{COOH} \\$

Acid palmitic acid has higher melting point, because it has two more methylene groups.

Giving it a greater surface area and therefore more intermolecular van der waals interact than the myristic acid.

stearic arid $\mathrm{CH}_3\left(\mathrm{CH}_2\right)_{16} \mathrm{COOH}$

linoleic acid $\mathrm{C}_{18} \mathrm{H}_{32} \mathrm{O}_2$ (two double bond)

Stearic acid has higher Melting point, because it does not have any Carbon-Carbon double bonds, whereas linoleic acid has two cis double bonds which prevent the molecules from packing closely together.

Oleic Acid and Linoleic acid.

$\mathrm{C}_{18} \mathrm{H}_{34} \mathrm{O}_2$ -one double bond (cis)