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bogdanovich [222]
2 years ago
6

​If you needed a 1.5 x 1 0-4 M solution of a compound that has a molar mass of 760 g/mol, what would it concentration be in part

s per million?
Chemistry
1 answer:
motikmotik2 years ago
6 0

Answer:

114 ppm

Explanation:

Data obtained from the question include:

Conc. of compound in mol/L = 1.5×10¯⁴ mol/L

Molar mass of compound = 760 g/mol

Conc. in ppm =..?

Next, we shall determine the concentration of the compound in grams per litre (g/L) . This is illustrated below:

Conc. in mol/L = conc. in g/L / Molar mass

1.5×10¯⁴ = conc. In g/L / 760

Cross multiply

Conc. in g/L = 1.5×10¯⁴ x 760

Conc. in g/L = 0.114 g/L

Next, we shall convert 0.114 g/L to milligrams per litre (mg/L). This is illustrated below:

1 g/L = 1000 mg/L

Therefore, 0.114 g/L = 0.114 x 1000 = 114 mg/L

Finally, we shall convert 114 mg/L to parts per million (ppm). This is illustrated below:

1 mg/L = 1 ppm

Therefore, 114 mg/L = 114 ppm

From the calculations made above,

1.5×10¯⁴ mol/L Is equivalent to 114 ppm.

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2 years ago
The IR spectrum of a solid can be taken by dissolving it to create a solution. An appropriate solvent is Choose... because its I
irina [24]

Answer:

An appropriate solvent is <u>only in the fingerprint region. </u>

Explanation:

For scientists to study the infrared spectra of substances in the various states of matter, solutions are usually made with solvents. However, it has been noted that some of these solvents can interfere with the reaction spectra or be absorbed within the range of the solutes. A solution to this problem is using the right solvents with non-interfering infrared spectrum and which have no chemical effect on the solute.

The bands formed by the solvent should also be located in the the fingerprint spectrum. Examples of solvents used to achieve this and which meet up these requirements include, Carbon tetrafluoride and Carbon disulfide.  

5 0
3 years ago
De acuerdo con la Ley de la Conservación de la Materia postulada por Lavoisier, ¿cuál ecuación química está balanceada? A C2H5OH
olya-2409 [2.1K]

Answer:

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

Explanation:

La ley de conservación de la materia implica que en una reacción química los átomos en los reactivos son iguales a la cantidad de átomos en los productos:

A C2H5OH(l) + O2(g) → CO2 + H2O

En los reactivos hay dos átomos de carbono pero en los productos solo 1. De esta manera, no cumple la ley de conservación.

B C2H5OH(l) + O2(g) → 2CO2 + H2O

En los reactivos hay 6 átomos de hidrógeno pero en los productos solo 2. No cumple la ley de conservación.

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos y productos hay: 2 átomos de carbono, 6 átomos de hidrógeno y 7 átomos de oxígeno. Cumple la ley de conservación.

D C2H5OH(l) + O2(g) → 2CO2 + 3H2O

En los reactivos hay 3 átomos de oxígeno y en los productos 7. No cumple la ley de conservación.

E 2C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

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6 0
3 years ago
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Answer:

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Explanation

8 0
3 years ago
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Consider the reaction. Upper H subscript 2 upper o (g) plus upper C l subscript 2 upper O (g) double-headed arrow 2 upper H uppe
dedylja [7]

Answer:

Equilibrium constant for the reaction is 0.0892

Explanation:

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Eq   0.077M       0.077M           0.023M

Let's make the expression for Kc

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Kc= 0.023² / 0.077 . 0.077 = 0.0892

5 0
3 years ago
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