Technically, how would you know if any work was done on an object?

A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.6 m/s at ground level.

galina1969 [7]

Answer:

44.64 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.2\times 1180+80.6^2}\\\Rightarrow v=128.01\ m/s$

$v=u+at\\\Rightarrow 128.01=80.6+4.2t\\\Rightarrow t=\frac{128.01-80.6}{4.2}=11.29\ s$

Time taken to reach 1180 m is 11.29 seconds

$v=u+at\\\Rightarrow 0=128.01-9.8t\\\Rightarrow t=\frac{128.01}{9.8}=13.06\ s$

Time the rocket will keep going up after the engines shut off is 13.06 seconds.

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-128.01^2}{2\times -9.8}\\\Rightarrow s=836.05\ m$

The distance the rocket will keep going up after the engines shut off is 836.05 m

Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m

The rocket will fall from this height

$s=ut+\frac{1}{2}at^2\\\Rightarrow 2016.05=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{2016.05\times 2}{9.8}}\\\Rightarrow t=20.29\ s$

Time taken by the rocket to fall from maximum height is 20.29 seconds

Time the rocket will stay in the air is 11.29+13.06+20.29 = 44.64 seconds

5 0

3 years ago

A mass tied to the end of a 1.0 m-long string is swinging back and forth From its lowest point, the mass moves 4 cm to the right

ehidna [41]

Answer:

a) 2seconds.

Explanation:

The period of oscillation will not change . It will still be 2seconds although the length was doubled to 8cm.

This is because the amplitude does not change oscillation time.

5 0

3 years ago

Please do not round the numbers

slamgirl [31]

Answer:

1) λ = 24.7 cm, 2) f = 13.88 Hz, 3) L = 117.3 cm

Explanation:

1) This is a resonance process, that is, the wave going downwards will interfere with the wave going upwards.

This is a tube with one end closed and the other open, at the closed end there is a node and at the open end a belly, so the resonances are

L = λ / 4

λ = 4L 1st harmonic

λ = 4L / 3 third harmonic

λ = 4L / 5 fifth harmonic

λ = 4L / n ’ n’ odd number n ’= (2n +1)

the wavelength is requested for the eighth resonance n = 8, the corresponding prime number is

n ’= 2 8 +1

n ’= 17

we substitute

λ = 4 105/17

λ = 24.7 cm

2) the speed of the wave is related to the wavelength and frequency

v = λf

f = v /λ

f = 343 / 24.7

f = 13.88 Hz

3) the next resonance occurs for n = 9, so the prime number is

n ’= 2 9 +1

n ’= 19

L = n’ λ / 4

L = 19 λ / 4

We must suppose a value for the wavelength, if the wavelength is present in the tube and the length of the column increases, the resonance number increases

L = 19 24.7/4

L = 117.3 cm

8 0

3 years ago

GIVING BRAINLIEST ! answer quick !!!!! What is the mass of a 1000 N person on Ea

REY [17]

Answer:

225-Ib person weighs 1000 N

7 0

3 years ago

The first charge is pulling on the second. Is the second pulling on the first? Explain your reasoning

Alex73 [517]

Answer:

law of action and reaction.

Explanation:

In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.

In this case, when the first load pulls on the second, the second pulls on the first, the two forces are not canceled because each one is applied to a different body.

Therefore the magnitude of the forces is the same, but the direction is opposite and each one is applied in a body

7 0

3 years ago