Answer:
Diameter of wire = 0.00021 meters
Explanation:
Given the following data;
Number of windings = 30
Length of windings = 6.3 mm to meters = 0.0063 meters
To find the diameter of the wire, we would use this mathematical expression;
Length of windings = number of windings * diameter of wire
Substituting the values into the expression, we have;
0.0063 = 30 * diameter of wire
Diameter of wire = 0.0063/30
Diameter of wire = 0.00021 meters
0.014 liters = 14 milliliters.
Hope it helps!
Answer:
Q = 160.36[kJ], is the heat lost.
Explanation:
This is a thermodynamic problem where we can find the latent heat of vaporization, at a constant temperature of 100 [°C].
We know that for steam at 100[C], the enthalpy is
![h_{gas} = 2675.6[kJ/kg]](https://tex.z-dn.net/?f=h_%7Bgas%7D%20%3D%202675.6%5BkJ%2Fkg%5D)
For liquid water at 100[C], the enthalpy is
![h_{water} = 419.17[kJ/kg]](https://tex.z-dn.net/?f=h_%7Bwater%7D%20%3D%20419.17%5BkJ%2Fkg%5D)
Therefore
![h_{g-w} = 2675.6-419.17 = 2256.43[\frac{kJ}{kg} ]](https://tex.z-dn.net/?f=h_%7Bg-w%7D%20%3D%202675.6-419.17%20%3D%202256.43%5B%5Cfrac%7BkJ%7D%7Bkg%7D%20%5D)
The amout of heat is given by:
![Q=h_{g-w}*m\\ where:\\m = mass = 0.07107[kg] = 71.01[g]\\Q = heat [kJ]\\Q =2256.43*0.07107\\Q=160.36[kJ]](https://tex.z-dn.net/?f=Q%3Dh_%7Bg-w%7D%2Am%5C%5C%20where%3A%5C%5Cm%20%3D%20mass%20%3D%200.07107%5Bkg%5D%20%3D%2071.01%5Bg%5D%5C%5CQ%20%3D%20heat%20%5BkJ%5D%5C%5CQ%20%3D2256.43%2A0.07107%5C%5CQ%3D160.36%5BkJ%5D)
Answer:
Option B is correct.
Explanation:
The resistance of a material or wire is represented by the formula below.
R=(ρL)/A
where
- R is resistance of wire
- ρ is the resistivity of the material
- A is the cross sectional area of wire
- L is length of wire
Resistance increases with increase in length and resistivity which means options C and D are wrong.
A=(π
)/4
An increase in diameter will result in a proportional increase in area
From the resistance formula, an increase in area will cause a reduction in the resistance of the material.Thus increased diameter of wire will lower the resistance of wire. Option B is correct
Have a great day
<span>So we want to know how much work is needed to move a charge Q=3C for a distance r=0.01m trough a potencial difference U=9V. Work of electric potential is defined as W=Q*U and we can now simply put in the numbers. We get: W=3C*9V=27J. So the correct answer is (2) 27J. </span>