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AlekseyPX
3 years ago
9

If you had an aqueous mixture that contained Ag+ , K+ , and Pb2+ cations, how many different solids could precipitate if a chlor

ide solution was added?
Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
3 0

Answer:

Two, KCl and PbCl₂.

Explanation:

Hello!

In this case, since the addition of chloride ions promote the following three ionic reactions:

Ag^+(aq)+Cl^-(aq)\rightleftharpoons AgCl(s)\\\\K^+(aq)+Cl^-(aq)\rightleftharpoons KCl(aq)\\\\Pb^{2+}(aq)+Cl^-(aq)\rightleftharpoons PbCl_2(s)

We can infer that both silver chloride and lead (II) chloride are precipitated products as their Ksp are 6.56x10⁻⁴ and 1.59x10⁻⁵ respectively, which means they are merely soluble in water.

Best regards!

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A 1.167 grams sample of hydrated Nickel (II) Chloride is heated until a constant mass is achieved. The constant mass of the samp
svetoff [14.1K]

Answer:

NiCl₂·4H₂O, its name being nickel (II) chloride tetrahydrate.

Explanation:

The constant mass achieved after heating is the mass of anhydrous nickel (II) chloride, NiCl₂. While the mass lost was water.

  • Mass lost = 1.167 g - 0.750 g = 0.417 g

Now we <u>convert 0.750 g of NiCl₂ into moles</u>, using <em>its molar mass</em>:

  • 0.750 g NiCl₂ ÷ 129.6 g/mol = 0.0058 mol NiCl₂

Then we <u>convert 0.417 g of H₂O into moles</u>:

  • 0.417 g H₂O ÷ 18 g/mol = 0.0231 mol H₂O

With the above information we can calculate that the number of H₂O moles is 4 times higher than the number of NiCl₂ moles.

Meaning that <em>the formula of the hydrate is NiCl₂·4H₂O</em>, its name being nickel (II) chloride tetrahydrate.

6 0
3 years ago
Pine trees slightly prefer slightly acidic soil. What happens if the pH changes to above 7?​
egoroff_w [7]

Answer:

The trees' growth might be affected

Explanation:

A pH above 7 indicates that the soil is no more acidic and that it had turned basic or alkaline in nature. This may affect the functioning of enzymes as this value is very far from optimum pH value. Thus growth is affected.

7 0
3 years ago
Read 2 more answers
A child is swinging back and forth on a swing. Changes in her kinetic and potential energy are happening each moment. At which p
dedylja [7]

Answer:

The maximum potential energy of the child will be maximum at the two end points.  

The maximum kinetic energy of the <em>child </em>occurs at the lowest point of the swing.  

The potential energy of the child depends on the displacement of the child.  

P.E = mgh  

The maximum height attained occurs at the two end points of her swing motion.  

Thus, the maximum potential energy of the child will be maximum at the two end points.

The kinetic energy of the child depends on the velocity of the child  

K.E = ¹/₂mv²  

The maximum velocity of the swing occurs at the lowest point of the swing.  

Thus, the maximum kinetic energy of the child occurs at the lowest point of the swing.

Hope this helps!

5 0
3 years ago
Read 2 more answers
An insulated piston-cylinder device contains 1 L of saturated liquid water at pressure of 150 kPa. An electric resistance heater
miskamm [114]

Answer:

Explanation:

In this problem,

we will determine the enthalpy at the end of heat input and we get the condition is the super heated state.

so the entropy change will be due to latent heat at 150 kPa and also due to temperature change at the super heated state.

All the temperature, enthalpy is evaluated with the help of the steam table.

mass is calculated with the help of a specific volume at initial condition.

<u>see image below</u>

3 0
3 years ago
How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?
nalin [4]

Answer:

V₁  = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁  =  0.10 M×300.0 mL

3.0 M ×V₁  = 30 M.mL

V₁  = 30 M.mL /3.0 M

V₁  = 10 mL

3 0
3 years ago
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