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vova2212 [387]
3 years ago
6

Which of the following is an example of a phase?

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

An example of a phase is the final part of a multiple part landscaping project. An example of a phase is when you can the various shapes of the moon. An example of phase is a period of time during which you are a teenager when you fight with your parents all the time.

Explanation:

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Which of the following would be found ONLY in plant cells
marin [14]

Answer:

chloroplasts, cell walls, or intracellular vacuoles

Explanation:

You didn't list the following, but I'm guessing it is chloroplasts, cell walls, or intracellular vacuoles

5 0
2 years ago
The valence electrons occur in what part of the atom?
shutvik [7]
The correct answer to the question that is stated above is letter  c, <span> the outer electron shell.</span>

Valence electrons occur<span> in the outermost shells of an </span>atom.

>> <span>Valence electrons are </span>electrons<span> that are associated with an </span>atom<span>, and that can participate in the formation of a </span>chemical bond.
7 0
3 years ago
Read 2 more answers
8.43g of CaCl2·2H2O is dissolved in 40.0g of H2O. What is the molality of the solution? (Note that the H2O in the CaCl2·2H2O mus
lara31 [8.8K]

Answer:

[CaCl₂·2H₂O] = 1.43 m

Explanation:

Molality is mol of solute / kg of solvent.

Mass of solvent = 40 g

Let's convert g to kg → 40 g / 1000 = 0.04 kg

Let's determine the moles of solute (mass / molar mass)

8.43 g / 146.98 g/mol = 0.057 mol

Molality = 0.057 mol / 0.04 kg → 1.43

3 0
3 years ago
Read 2 more answers
A hot lump of 30.5 g of iron at an initial temperature of 52.7 °C is placed in 50.0 mL H2O initially at 25.0 °C and allowed to r
slava [35]

Answer:

26.7°C

Explanation:

Using the formula; Q = m × c × ΔT

Where; Q = amount of heat

m = mass

c = specific heat

ΔT = change in temperature

In this question involving iron placed into water, the Qwater = Qiron

For water; m= 50g, c = 4.18 J/g°C, Initial temp= 25°C, final temp=?

For iron; m = 30.5g, c = 0.449J/g°C, Initial temp= 52.7°C, final temp=?

Qwater = -(Qiron)

m × c × ΔT (water) =- {m × c × ΔT (iron)}

50 × 4.18 × (T - 25) = - {30.5 × 0.449 × (T - 52.7)}

209 (T - 25) = - {13.6945 (T - 52.7)}

209T - 5225 = -13.6945T + 721.7

209T + 13.6945T = 5225 + 721.7

222.6945T = 5946.7

T = 5946.7/222.6945

T = 26.7

Hence, the final temperature of water and iron is 26.7°C

8 0
3 years ago
Heating oxygen difluoride gas yields oxygen gas and fluorine gas? Whats the balance chemical equation for this?
N76 [4]
2OF2(g) —> O2(g) + 2F2(g) hope that helps
5 0
3 years ago
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