Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system.
Answer:
Explanation:
<u>1) Reactants:</u>
The reactants are:
- <em>Molecular chlorine</em>: this is a gas diatomic molecule, i.e. Cl₂ (g)
- <em>Molecular fluorine</em>: this is also a gas diatomic molecule: F₂ (g)
<u>2) Stoichiometric coefficients:</u>
- <em>One volume of Cl₂ react with three volumes of F₂</em> means that the reaction is represented with coefficients 1 for Cl₂ and 3 for F₂. So, the reactant side of the chemical equation is:
Cl₂ (g) + 3F₂ (g) →
<u>3) Product:</u>
- It is said that the reaction yields <em>two volumes of a gaseous product;</em> then, a mass balance indicates that the two volumes must contain 2 parts of Cl and 6 parts of F. So, one volume must contain 1 part of Cl and 3 parts of F. That is easy to see in the complete chemical equation:
Cl₂ (g) + 3F₂ (g) → 2Cl F₃ (g)
As you see, that last equation si balanced: 2 atoms of Cl and 6 atoms of F on each side, and you conclude that the formula of the product is ClF₃.
The correct answer is B. Solubility describes the amount of solute that can be dissolved in a solvent. This value is not constant is affected by many factors. One factor is the temperature. An increase in temperature, a corresponding change in solubility also can be observed. The increase leads to a decrease in the solubility and the opposite. A decrease is observed since gas molecules are now has enough energy to escape the liquid phase and go to the gas phase.
In order to find out the %mass dolomite in the soil,
calculate for the mass of dolomite using the information given from the
titration procedure. You would need to multiply 57.85 ml with 0.3315 M HCl and
you would get the amount of HCl in millimoles. Then multiply the amount of HCl
with 1/2 (given that for every 1 mol of dolomite, 2 mol of HCl would be
needed). Convert the amount of dolomite to mass by multiplying the millimoles
with the molecular weight which is 184.399. Then convert the mass to grams
which is 1.768 grams. Divide the mass of dolomite (1.768 grams) with the weight
of soil sample. The % mass is 7.17.
