Answer:
The correct answer is-
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
2. Two genes, with a dominant allele at either or both loci.
Explanation:
The given information gives THE following data:
Dominant: Lancerate leaves - AABB
Recessive: normal leaves - aabb
F1 has - all Lacerated leaves - AaBb
F2 by selfing F1:
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94
And normal 1/16 = 0.062 is almost same as 16/265 = 0.060
Thus, the genotypes of -
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
Alleles refer to the DNA!! So B!
The three cellular components, which takes part in the process of metabolism and are affected by the modifications in temperature are ribosomes, cell membrane, and enzymes.
All these are formed of a certain type of protein, which can become denatured when exposed to high enough heat or stop gets functioning at too low temperature. The high temperature can disrupt the non-polar hydrophobic interactions and hydrogen bonds. This takes place as heat enhances the kinetic energy and makes the molecules to throb so briskly and viciously that the bonds get disordered.
Incomplete dominance produces a new heterozygous phenotype such as the purple color in this example
C) I and III only just got this question on usa test prep and therefore i'm right
