8r and 4r are like terms since they both have an r
also 3s and -3s are also like terms because of the s
Answer:
67.5feet
Step-by-step explanation:
Given parameters:
Model distance between building and gymnasium = 22.5 inches
Scale of model : 1 inch = 3 feet
Unknown:
Actual ground distance = ?
To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.
In this problem;
the scale is given as;
1 inch on model represents 3 feet on ground
Now, to find 22.5 inches, simply cross multiply and solve;
If 1 inch on model represents 3 feet on ground
22.5 inches on a model will be = 
= 67.5feet
Therefore, the actual distance is 67.5feet
For the 1st one we need to solve x. x-y=2 step1: x-y+y=2+y answer: x=y+2
Radius =
<span>
<span>
<span>
23.125
</span>
</span>
</span>
cm
Cylinder Volume = <span>π <span>• r² • height
</span></span>
Cylinder Volume = 3.14 * 23.125^2 * 18.5
Cylinder Volume =
<span>
<span>
<span>
31,064.53515625
</span>
</span>
</span>
Cylinder Volume =
<span>
<span>
<span>
31,064.54 cubic centimeters
</span></span></span>
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