Let X be the score on an english test which is normally distributed with mean of 31.5 and standard deviation of 7.3
μ = 31.5 and σ =7.3
Here we have to find score that separates the top 59% from the bottom 41%
So basically we have to find here x value such that area above it is 59% and below it is 49%
This is same as finding z score such that probability below z score is 0.49 and above probability is 0.59
P(Z < z) = 0.49
Using excel function to find the z score for probability 0.49 we get
z = NORM.S.INV(0.49)
z = -0.025
It means for z score -0.025 area below it is 41% and above it is 59%
Now we will convert this z score into x value using given mean and standard deviation
x = (z* standard deviation) + mean
x = (-0.025 * 7.3) + 31.5
x = 31.6825 ~ 31.68
The score that separates the top 59% from the bottom 41% is 31.68
Answer:
3 Miles
Step-by-step explanation:
The Median is the middle value of whatever data set, which means the median is 3 since its the middle value
Could you please show the question so I can try to answer it
Answer:
x^12 y^2 z^11
a= 12
b= 2
c= 11
Step-by-step explanation:
On the numerator you distribute the exponent 3 to the other exponents.
I think you multiply the 3 so you would get: x^15 y^3 z^12.
so it looks like x^15 y^3 z^12 / x^3yz
Then you subtract the top exponents from the bottom exponent because when you are dividing you subtract exponents. the exponent for y and z in the denominator is 1
and thats how i got x^12 y^2 and z^11. The exponents are a b and c
I hope that is right
