First compute the number of grams of manganese metal required to make 21.7 grams of H2.
21.7 g H2 x (1 mole H2/ 2 g H2) x (1 mole Mn/1 mol H2) x (55 grams Mn/1 mol Mn) = 596.75 grams
Now density = mass/volume
7.43 = 596.75/volume
volume = 596.75/7.43 = 80.31 mL
80.31 mL is the amount of manganese needed.
Im pretty sure that the current will increase so the answer is A . Hope that helps
Answer:
It's because they are easily carried by the wind.
<u><em>Hope I helped :)</em></u>
Answer:
b. some sodium iodide will precipitate out of solution
Explanation:
We know that for salts solubility decreases as the temperature of the solution decreases. So, NaI being a salt, its solubility will surely decrease when the temperature is cooled down to 25°C from 50°C.
Thus,the undissolved sodium iodide will precipitate out of the solution.
Answer:
P₂ = 0.11 atm
Explanation:
Given data:
Initial pressure = 0.12 atm
Initial temperature = 294 K
Final pressure = ?
Final temperature = 273 K
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.12 atm / 294 K = P₂/273 K
P₂ = 0.12 atm × 273 K / 294 K
P₂ = 32.76 atm. K /294 K
P₂ = 0.11 atm
