Alkenes can be converted to alcohols by hydroboration–oxidation. Draw a structure showing one of the alcohols formed in the foll
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<h2>~<u>Solution</u> :-</h2>
- Here, to find the atomic mass of element, we must;
We know that,
- 4.6 x $ \sf{10^{22}}$ atoms of an element weigh 13.8g.
Thus,
The atoms of $ \sf{ 6.02 \times 10^{13}}$ will weigh;
- Hence, the molar mass (atomic mass) will be <u>180.6 g.</u>
<u>Answer:</u> The amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of hex-3-ene = 5.84 g
Molar mass of hex-3-ene = 82.14 g/mol
Putting values in equation 1, we get:
The chemical equation for the conversion of hex-3-ene to 3-hexanol follows:
By Stoichiometry of the reaction:
1 mole of hex-3-ene produces 1 mole of 3-hexanol
So, 0.0711 moles of hex-3-ene will produce = of 3-hexanol
Now, calculating the mass of 3-hexanol from equation 1, we get:
Molar mass of 3-hexanol = 102.2 g/mol
Moles of 3-hexanol = 0.0711 moles
Putting values in equation 1, we get:
To calculate the percentage yield of 3-hexanol, we use the equation:
Experimental yield of 3-hexanol = 4.33 g
Theoretical yield of 3-hexanol = 7.27 g
Putting values in above equation, we get:
Hence, the amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %