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2 years ago

Where are the alkali metals, the alkaline earth metals, the halogens, and the noble gases located on the periodic table?

1 answer:

3 0

The Alkali Metals- (Group 1A)can be found (excluding hydrogen) in the first column of the periodic table. They all have 1 valence electron and tend to form +1 cations when forming Ionic bonds with non metals.

The Alkali Earth Metals: (Group 2A) can be found in the second column/group on the periodic table. These elements form +2 positively charged cations when forming Ionic bonds with non metals. They also all have 2 valence electrons.

The Halogens: are the elements that make up the second to last group on the periodic table. These elements include Chlorine, Fluorine, Bromine, Iodine, and Astatine. These elements have 7 valence electrons. The usually form a -1 charged anion when forming ionic bonds with metals.

The Noble gases: the very last group on the periodic table. All these elements have 8 valance electrons. Due to the octet rule these atoms are already very stable and rarely react with other elements.

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How to do it???????????

amm1812

Tempratures

1. -60 C = 213.15 K

2. 250 C= 523.15 K

3. 365 K = 91.85 C

4. 205 K = -68.15 C

Pressures

1. 22.0 inches Hg = 558.8 mm Hg

2. 3.4 atm = 2584 mm Hg

3. 680 mm Hg = 0.894737 atm

4. 785 mm Hg = 104.658 kPa

Hope this helped! Please mark as brainliest! Thanks!

Although It showes I'm a begginer, I was An Ace, till my account got deleted.

My name was Sorry14.

4 0

2 years ago

The partial Lewis structure that follows is for a hydrocarbon molecule. In the full Lewis structure, each carbon atom satisfies

ahrayia [7]

Answer:

$C-C> C=C> C\equiv C$

So, 2 $>$ 1 $>$ 3

Explanation:

Carbon is a non-metal and has 6 electrons. In the excited state, it contains 4 electrons in its outermost shell and so 4 electrons take place in covalent bond formation. In a molecule , 2 carbon atoms can be bound by a single bond, the double bond and by a triple bond. Since the bond length of $C\equiv C$ is 120 pm, the bond length of $C=C$ is 134 pm and the bond length of $C-C$ is 154 pm. Thus in the given compound, $C= C-C\equiv C$ , in which $C= C$ is labeled as 1, $C-C$ is labeled as 2 and $C\equiv C$ is labeled as 3. So the bond length of carbon-carbon bonds in the molecule, in decreasing order is $2 > 1 >3$ .

8 0

2 years ago

What is oribital velocity

Sveta_85 [38]

orbital velocity is a velocity that causes a natural or artificial satellite to remain in orbit

it can also be defined as the velocity at which a body revolves about another body

hope that helps !

4 0

2 years ago

The filament is the main structure, which is made up of the stamen with the anther on top.

pentagon [3]

It correctly describes the male reproductive parts.
Eunice switched the stamen and the anther.
Eunice switched the filament and the stamen.
It correctly describes the female reproductive parts.

6 0

2 years ago

Consider the reaction when aqueous solutions of magnesium sulfate and chromium(iii) acetate are combined. (use the solubility ru

WARRIOR [948]

Answer : When we mix the aqueous solutions of magnesium sulfate with chromium acetate we get the following reaction :-

$MgSO _{4} + Cr (C _{2}H _{3}O _{2}) _{2} ----\ \textgreater \ CrSO _{4} + Mg(C _{2}H _{3}O _{2}) _{2}$

It is an example of a displacement reaction that takes place. According to the OWL solubility preparation rules all the reactants are soluble and hence the reaction occurs.

The net ionic equation of the reaction is :-

$SO _{4} ^{-2} _{(aq.)} + Cr^{+2} _{(aq.)} ----\ \textgreater \ CrSO_{4}_{(s)}$

7 0

2 years ago