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abruzzese [7]
4 years ago
8

The half-life of radioactive element krypton-91 is 10 seconds. if 16 grams of krypton-91 are initially present, how many grams a

re present after 10 seconds? after 50 seconds?
Chemistry
1 answer:
earnstyle [38]4 years ago
6 0
10 seconds = 8grams
then just divide by 2 another 4 times...
 = 0.5grams after 50 seconds
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cluponka [151]

Answer:

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Explanation:

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1st step Ballance the equation. Afterwards, you can work properly

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2nd step Predict the reactant in excess and limitant reagent.

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I have 9 moles of CO, so the Fe2O3 is my limitant reagent.

<u><em>REMEMBER</em></u> you always have to work with the limitant.

If 3 moles of CO reacts with 1 mol of Fe2O3

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I have 2 moles of Fe2O3, so I still have Fe2O3, by the way the CO is the reactant in excess. (Just to show all)

3rd step Work with the limitant reagent.

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2 mol of Fe2O3 ___ makes ___ 4 moles of Fe  +  6 moles of CO

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