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4 years ago

Kinetic or potential energy.

Chemistry

2 answers:

Irina18 [472]4 years ago

4 0

Answer:

Potential energy is the energy in a body due to its position. While kinetic energy is the energy in a body due to its motion.

Roman55 [17]4 years ago

4 0

Whats the question , i’m confused ?

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Sulfonation of benzene has the following mechanism:(b) Write the overall rate law in terms of the initial rate of the reaction.

erica [24]

The overall rate law in terms of the initial rate of the reaction is:

= $k_{overall} [H_{2} SO_{4} ]^{2} [C_{6}H_{6}]$

The Sulfonation of benzene has the following mechanism:

(1) $2H_{2} SO_{4}$ ⇌ $H_{3}O^{+} + HSO_{4} + SO_{3}$

[fast]

(2) $SO_{3} + C_{6} H_{6}$ → $H(C_{6} H_{5}^{+} )SO_{3}^{-}$

[slow]

(3) $H(C_{6} H_{5}^{+} )SO_{3}^{-}$ $+ HSO_{4}^{-}$ → $C_{6} H_{5} SO_{3}^{-} + H_{2} SO_{4}$

[fast]

(4) $C_{6} H_{5} SO_{3}^{-} + H_{3}O^{+}$ → $C_{6} H_{5} SO_{3} H + H_{2} O$

[fast]

<h3>Calculation of rate law:</h3>

Given that the reaction's slowest step is the rate-dependent step, the following is the definition of rate law:

Rate = $k_{2} [SO_{3} ][C_{6} H_{6} ]$

However, the issue is that because $SO_{3}$ is an intermediate, it cannot be accounted for in the general rate legislation.

The following rate rule governs the synthesis of $SO_{3}$ :

Rate = $k_{1}[H_{2} SO_{4} ]^{2}$

Consequently, if we replace equation 1 with equation 2,

Rate is determined to be = $k_{overall} [H_{2} SO_{4} ]^{2} [C_{6}H_{6}]$

Hence, the overall rate law in terms of the initial rate of the reaction is:

= $k_{overall} [H_{2} SO_{4} ]^{2} [C_{6}H_{6}]$

Learn more about rate law here:

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hope this helps!

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