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Physics

2 answers:

Tom [10]2 years ago

8 0

Answer:

the answer its time

v = d/t

Ghella [55]2 years ago

8 0

Answer:distance

Explanation:

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At the equator earth rotates with a velocity of about 465 m/s.

Dafna1 [17]

The given velocity is 465 m/s.

Part a.
$465 \, \frac{m}{s} =(465 \times 10^{-3} \, \frac{km}{s})*( 3600 \, \frac{s}{h} ) = 1674 \, \frac{km}{h}$
Answer: 1674 km/h

Part b.
$1674 \frac{km}{h} = (1674 \, \frac{km}{h})*(24 \, \frac{h}{day} ) = 40176 \, \frac{km}{day}$
Answer: 40,176 km/day.

3 0

3 years ago

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Convert planks constant in cgs system

dezoksy [38]

in cgs system, plank's constant= h=6.626 x10⁻²⁶ erg s

Value of Plank's constant in SI system= 6.626 x10⁻³⁴ Js

now 1 Joule= 10⁷ ergs

so h= 6.626 x10⁻³⁴ Js (10⁷ ergs/1J)

h=6.626 x10⁻²⁷ erg s

7 0

3 years ago

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. a

USPshnik [31]

Refer to the diagram shown below.

Let I = the moment of inertia of the wheel.
α = 0.81 rad/s², the angular acceleration
r = 0.33 m, the radius of the weel
F = 260 N, the applied tangential force

The applied torque is
T = F*r
= (260 N)*(0.33 m)
= 85.8 N-m

By definition,
T = I*α

Therefore,
I = T/α
= (85.8 N-m)/(0.81 rad/s²)
= 105.93 kg-m²

Answer: 105.93 kg-m²