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3 years ago

If it takes 10 seconds for a car to reach its top speed of 100 miles per hour, its acceleration would be. Help please

Physics

1 answer:

hjlf3 years ago

4 0

Answer:

$36000 miles/h^{2}$ or $0.0028 miles/s^{2}$

Explanation:

Acceleration is rate of change of speed per unit time. The change in speed is given by deducting the initial speed from final speed. Assuming that the car starts from rest to a top speed of 100 miles per hour, then the change in speed is equivalent to 100-0=100 miles per hour.

Time is given in seconds and converting to hours will be 10/3600

The acceleration will then be

$\frac {100*3600}{10}=36000 miles/h^{2}$

Alternatively, the change in speed xould be converted to miles per second hence 100/3600 miles per second divided by 10 s then $a=\frac {100}{36000}=0.0027777777777 m/s^{2}$ rounded off as $0.0028 miles/s^{2}$

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Applying Coulomb's formula for $q_1$ is

$\displaystyle F_{13}=\frac{k\ q_1\ q_3}{d_1^2}$

Now for $q_2$

$\displaystyle F_{23}=\frac{k\ q_2\ q_3}{d_2^2}$

If the total force on $q_3$ is zero, both forces must be equal. Note that being q2 negative, the force on q3 is to the right. The force exerted by q1 must go to the left, thus q1 must be positive. Equating the forces we have:

$\displaystyle F_{13}=F_{23}$

$\displaystyle \frac{k\ q_1\ q_3}{d_1^2}=\frac{k\ q_2\ q_3}{d_2^2}$

Simplfying and solving for $q_1$

$\displaystyle q_1=\frac{q_2\ d_1^2}{d_2^2}$

$\displaystyle q_1=\frac{3.10^{-9}\ 0.02^2}{0.04^2}$

$\boxed{\displaystyle q_1=+0.375\ {10}^{-9}}$

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