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inna [77]
3 years ago
8

If it takes 10 seconds for a car to reach its top speed of 100 miles per hour, its acceleration would be. Help please

Physics
1 answer:
hjlf3 years ago
4 0

Answer:

36000 miles/h^{2} or 0.0028 miles/s^{2}

Explanation:

Acceleration is rate of change of speed per unit time. The change in speed is given by deducting the initial speed from final speed. Assuming that the car starts from rest to a top speed of 100 miles per hour, then the change in speed is equivalent to 100-0=100 miles per hour.

Time is given in seconds and converting to hours will be 10/3600

The acceleration will then be

\frac {100*3600}{10}=36000 miles/h^{2}

Alternatively, the change in speed xould be converted to miles per second hence 100/3600 miles per second divided by 10 s then a=\frac {100}{36000}=0.0027777777777 m/s^{2} rounded off as 0.0028 miles/s^{2}

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The correct options are:

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"Radio waves have a lower frequency, which makes them safer for humans."

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"Radio waves take less energy to produce."

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Radio waves are electromagnetic waves with frequencies on the range from 10 KHz to 10 THz.

Now, remember that all electromagnetic waves have the same speed, which is the speed of light, and the energy of a wave is proportional to its frequency.

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With that in mind, the correct options are.

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4 0
2 years ago
The Kentucky Derby, the first leg of horse racing’s Triple Crown, was won by a time of 122.2 s. If the race covers 2011.25 m, wh
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3 0
3 years ago
Read 2 more answers
To push a 26.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of 209 N parallel
alukav5142 [94]

Answer:

(a) W = +397.1 J

(b) W = -204.6 J

(c) W = 0

(d) W= + 192.5 J

Explanation:

Work (W) is defined as the product of force (F) by the distance (d)the body travels due to this force. :

W= F*d Formula ( 1)

The forces that perform work on an object must be parallel to its displacement.

The forces perpendicular to the displacement of an object do not perform work on it.

The work is positive (W+) if the force has the same direction of movement of the object.  

The work is negative (W-) if the force has the opposite direction of the movement of the object.

Problem development

(a) Work performed by the worker's applied force on the box .

W= 209 N * 1.9 m = +397.1 J

(b) Work performed by the gravitational force on the crate

We calculate the weight component parallel to the displacement of the box:

We define the x-axis in the direction of the inclined plane ,25.0° to the horizontal.

We define the y-axis and in the direction of the plane perpendicular to the inclined plane.

W= m*g=26*9.8= 254.8N : total box weight

Wx= W*sen25.0°= 254.8*sen25.0°= 107.68 N

W = -Wx *d =107.68 N *1.9 m= -204.6 J

(c) Work performed by normal force (N) exerted by the incline on the crate

The force N is perpendicular to the displacement, then:

W=0

(d) Total work done on the crate

W = 397.1 J -204.6 J

W = 192.5 J

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3 years ago
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