Which type of elements are likely to have no electical charge at all
2 answers:
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Answer: 62.22 meters
Explanation:
Two solve this, we need to know first how the Sled interact with the snow. While the Sled runs over the snow, the snow opposes to it movement, this is call friction. Frictions creates is a force that goes against any movement and is caused by the interaction between surfaces.
Friction can be calculated using the following equation:
Friction's Force (Ff) = m*N
Where m is the Frictions coficient and N is call Normal, which is a force created by the contact between any weight and a surface. Because the sled is and the surface are totally horizontal, the Normal is equal to the Sled's Weight.
So for this case, we can calculate the Friction's Force:
Ff = 0.045 * 735 N
Ff = 33,07 N
This force will cause a negative acceleration the Sled causing it to slow down and finally stop. To know this accelaration we can use the following equation:
Force (F) = Mass (m) * Accelaration (a)
Looking for the accelaration:
Acceleration (a) = F / M
As a side note:
Mass (M) = F / a (1)
Where we know that F is equal to our Friction Force (Ff) and the Mass for the girl and the Sled can be obtained using the previous equation (1) like this
Girl and sled Mass (M) = 735 N / (9.81 m/s)
M = 74,92 Kg
This is posible, because the Girl and The Sled are aplying a Force on the ground equal to 735 N. The accelartion for their mass is the gravity
Now, with the mass we can found the Accelaration caused by friction:
Acceleration (a) = Ff / M
Accelaration (a) = 33,07 N / 74,92 Kg
a = 0,44
To know how far the Sled travel we can use the following equation:
Where Vf is the Final Velocity, which is when the sled finally stops (Vf = 0), Vo is the Initial Speed of the Sled equal to 7.4 m/s and a is equal to the negative accelaration that causes the friction.
Searching for x:
The girls will run over the snow 62.22 meter until finally stopping
Answer:
t = 2.77 s
Explanation:
The ball in its movement describes a curved line called a semiparabola, therefore two coordinates are required to fix the position at each instant of time, since the movement is performed in the X-Y plane:
Equation of movement of the ball in the X axis
X = v₀x*t Equation (1)
Equation of movement of the ball in the Y axis
Y = y₀+ v₀y*t -½ g*t² Equation (2)
Where
X : horizontal position in meters (m)
Y : vertical position in meters (m)
y₀ : initial vertical position in meters (m)
v₀x : X-initial speed in m/s
v₀y : Y-initial speed in m/s
g: acceleration due to gravity in m/s²
t : time to position (X,Y)
Data
y₀ = 37.5 m
v₀y = 0
g = 9.8 m/s²
Problem development
The time the ball remains in the air is the same as the ball takes to touch the floor, that is, Y = 0
We apply the Equation (2):
Y = y₀+ (v₀y)*t - (½) g*t²
0 = 37.5 +(0)*t- (1/2)*(g)*t²
0 = 37.5 - (1/2)*(9.8)*t²
(1/2)*(9.8)*t² = 37.5
t² = (2)(37.5)/(9.8)
t = 2.77 s