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emmasim [6.3K]
3 years ago
11

Can someone help me match them

Chemistry
1 answer:
ozzi3 years ago
6 0

1: shield volcano: 2

2: cinder cone volcano :3

3 : composite volcano : 1

Mark me as brainlist

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How can scientists control the flammability of a substance?
mamaluj [8]

Answer: This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.

Explanation:

May i have brainliest please and don't forget to drop a heart

8 0
3 years ago
Which activity performed by a medical professional is primarily based on an understanding of physics
scoundrel [369]

MRI scanning, CAT scanning, radiotherapy, conventional X-ray imaging, ultrasound scans and ultrasound therapy.

3 0
3 years ago
Small quantites of hydrogen gas can be prepared in the laboratory by the addition of aqueous hydrochloric acid to metallic zinc.
ira [324]

<u>Answer:</u> The mass or zinc reacted is 0.624 grams.

<u>Explanation:</u>

We are given:

Total pressure = 1.032 atm

Vapor pressure of water = 32 torr = 0.042 atm    (Conversion factor:  1 atm = 760 torr)

To calculate partial pressure of hydrogen gas, we use the equation:

p_{H_2}=p_T-p_{H_2O}\\\\p_{H_2}=1.032-0.042=0.99atm

To calculate the number of moles of hydrogen gas, we use the equation given by ideal gas follows:

PV=nRT

where,

P = pressure of hydrogen gas = 0.99 atm

V = Volume of hydrogen gas = 240. mL = 0.240 L    (Conversion factor: 1 L = 1000 mL)

T = Temperature of hydrogen gas = 30^oC=[30+273]K=303K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

0.99atm\times 0.240L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 303K\\n=\frac{0.99\times 0.240}{0.0821\times 303}=9.55\times 10^{-3}mol

The chemical equation for the reaction of zinc and hydrochloric acid follows:

Zn+2HCl\rightarrow ZnCl_2+H_2

By Stoichiometry of the reaction:

1 mole of hydrogen gas is produced from 1 mole of zinc metal

So, 9.55\times 10^{-3}mol of hydrogen gas is produced from = \frac{1}{1}\times 9.55\times 10^{-3}=9.55\times 10^{-3}mol of zinc metal

To calculate the mass of zinc metal, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of zinc = 65.38 g/mol

Moles of zinc = 9.55\times 10^{-3} moles

Putting values in above equation, we get:

9.55\times 10^{-3}mol=\frac{\text{Mass of zinc}}{65.38g/mol}\\\\\text{Mass of zinc}=(9.55\times 10^{-3}mol\times 65.38g/mol)=0.624g

Hence, the mass or zinc reacted is 0.624 grams.

4 0
4 years ago
Express as ordinary numbers.<br> 3 x 10^0 =
liq [111]

Answer:

the answer is 3

Explanation:

hope this works

7 0
3 years ago
The concentration of the stock solution she needs is 100 milli molar (mm) and she needs to make 1.2 milli liters (ml) solution o
Lera25 [3.4K]
Molarity is defined as the number of moles of solute in 1 L of solution 
molarity of stock solution to be prepared - 100 x 10⁻³ mol/L
volume of stock solution to be prepared - 1.2 mL 
Therefore number of moles in 1.2 mL - 100 x 10⁻³ mol/L x 1.2 x 10⁻³ L 
number of moles of drug - 1.2 x 10⁻⁴ mol 
mass of drug required - 1.2 x 10⁻⁴ mol x 181.6 g/mol = 21. 8 mg
21.8 g of drug is required to make the stock solution
6 0
3 years ago
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