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gulaghasi [49]
3 years ago
12

What do I do for the drawing, I honestly don't really know anything about this and find it extremely confusing???

Chemistry
2 answers:
Sav [38]3 years ago
6 0
Uhh ns, kind of confusing
marin [14]3 years ago
5 0

I also don't no really. I posted the picture of dilute and concentrate solution.See if it is or not.

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How many molecules of lactate can one molecule of lactate dehydrogenase act on in 21 minutes?
USPshnik [31]
The turnover number (number of molecules the enzyme can act on per second) for lactase dehydrogenase is 1,000 lactate molecules per second.
In one minute, this becomes:

(1,000 molecules / second) * (60 seconds / minute)
= 60,000 molecules / minute

In 21 minutes, this will be:

60,000 * 21

= 1.26 x 10⁶ molecules of lactate
6 0
4 years ago
How many atoms are there in 3.559*10^-6 mol of krypton?
algol [13]

Answer:

The answer is

<h2>2.143 \times  {10}^{18}  \:  \: atoms</h2>

Explanation:

To find the number of atoms given the number of moles we use the formula

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 3.559 \times  {10}^{ - 6}  \: mol

Substitute the values into the above formula and solve

That's

<h3>N  = 3.559 \times  {10}^{ - 6}  \times 6.02 \times  {10}^{23}  \\  = 2.1425 \times  {10}^{18}</h3>

We have the final answer as

<h3>N  = 2.143 \times  {10}^{18}  \:  \: atoms</h3>

Hope this helps you

3 0
4 years ago
Carry out electrolysis of dilute CuSO4 using copper electrodes. State the products formed at the electrodes and nature of the el
Arturiano [62]
I don’t this answer I just want points but hope someone answers this 6
7 0
3 years ago
When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, h
Pavel [41]
NH₃:

N = 8*10²²
NA = 6.02*10²³

n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol

O₂:

N=7*10²²
NA = 6.02*10²³

n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol

4NH₃                   <span>+                        3O</span>₂                      ⇒<span>          2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol                     :                        3mol                   :             2mol
0.133mol             :                        0.116mol           :             0,0665mol
limiting reactant

N₂:

n = 0.0665mol
M = 28g/mol

m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>
6 0
4 years ago
Which of these compounds are oxidizing agents?
elena55 [62]

i guess its e) Mn (VII)

if it was wrong pls let me knw


6 0
3 years ago
Read 2 more answers
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