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3 years ago

True or false electrons are a lot lower in mass than protons

Physics

2 answers:

Romashka [77]3 years ago

6 0

True, electrons are a lot lower in mass than protons.

slavikrds [6]3 years ago

4 0

True. The mass of an electron is about 1/2000 amu whereas the mass of a proton is 1 amu.

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Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

lara31 [8.8K]

Answer:

-22.2 m/s²

Explanation:

The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:

(1) $x=\frac{1}{2}at^2+v_0t+x_0$

For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:

(2) $0=\frac{1}{2}at^2+v_0t$

Solving for time t:

$-\frac{1}{2}at^2=v_0t$

(3) $t=-\frac{2v_0}{a}$

The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:

(4) $\frac{v_{0A}}{a_A}=\frac{v_{0B}}{a_B}$

Solving equation 4 for acceleration of rocket B:

(5) $a_B=a_A\frac{v_{0B}}{v_{0A}}$

3 0

3 years ago

What do simple machines accomplish

xz_007 [3.2K]

Answer:

not many things maybe they accomplish one job the machine has been programmed to do.

Explanation:

3 0

3 years ago

Read 2 more answers

What property of an electromagnetic wave changes when the wave is encoded with analog information?

Licemer1 [7]

Answer:

Amplitude and Frequency

Explanation:

Analog signals are composed of continuous waves that can have any values for frequency and amplitude. These waves are smooth and curved.

Radio transmissions are a combination of two kinds of waves: audio frequency waves that represent the sounds being transmitted and radio frequency waves that "carry" the audio information. All waves have a wavelength, an amplitude and a frequency as shown in the figure. These properties of the wave allow it to be modified to carry sound information.

The two most common types of modulation used in radio are amplitude modulation (AM) and frequency modulation (FM). Frequency modulation minimizes noise and provides greater fidelity than amplitude modulation, which is the older method of broadcasting . Both AM and FM are analog transmission systems, that is, they process sounds into continuously varying patterns of electrical signals which resemble sound waves.

7 0

2 years ago

Find average speed when time= 27s and total distance is 94m

Slav-nsk [51]

3.4814815 (or 3 13/27) m/s

speed = distance/time
3.4814815 (or 3 13/27) = 94/27

8 0

3 years ago

Two runners start at the same point on a straight track. The first runs with constant acceleration so that he covers 98 yards in

charle [14.2K]

Answer:

94.13 ft/s

Explanation:

<u>Given:</u>

$t$ = time interval in which the rock hits the opponent = 10 s - 5 s = 5 s

$s$ = distance to be moved by the rock long the horizontal = 98 yards

$y$ = displacement to be moved by the rock during the time of flight along the vertical = 0 yard

<u>Assume:</u>

$u$ = magnitude of initial velocity of the rock

$\theta$ = angle of the initial velocity with the horizontal.

For the motion of the rock along the vertical during the time of flight, the rock has a constant acceleration in the vertically downward direction.

$\therefore y = u\sin \theta t +\dfrac{1}{2}(-g)t^2\\\Rightarrow 0 = u\sin \theta 5 +\dfrac{1}{2}(-9.8)\times 5^2\\\Rightarrow u\sin \theta 5 =\dfrac{1}{2}(9.8)\times 5^2......(1)\\$

Now the rock has zero acceleration along the horizontal. This means it has a constant velocity along the horizontal during the time of flight.

$\therefore u\cos \theta t = s\\\Rightarrow u\cos \theta 5 = 98.....(2)\\$

On dividing equation (1) by (2), we have

$\tan \theta = \dfrac{25}{20}\\\Rightarrow \tan \theta = 1.25\\\Rightarrow \theta = \tan^{-1}1.25\\\Rightarrow \theta = 51.34^\circ$

Now, putting this value in equation (2), we have

$u\cos 51.34^\circ\times 5 = 98\\\Rightarrow u = \dfrac{98}{5\cos 51.34^\circ}\\\Rightarrow u =31.38\ yard/s\\\Rightarrow u =31.38\times 3\ ft/s\\\Rightarrow u =94.13\ ft/s$

Hence, the initial velocity of the rock must a magnitude of 94.13 ft/s to hit the opponent exactly at 98 yards.

3 0

3 years ago