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Verizon [17]
3 years ago
15

Will give braineliest

Mathematics
2 answers:
OleMash [197]3 years ago
7 0

Answer:

3Fx + 3Gy = 3H\\Qx + Ry = S

Step-by-step explanation:

Given:

The system of equations given are:

Fx + Gy = H \\Qx + Ry = S

If an equation is multiplied by a number throughout, then the equation remains the same by multiplication property of equality. The multiplication property of equality says that if both sides of the equation is multiplied by the same number, then the new equation is equivalent to the previous equation.

For example: If x+y =2 is multiplied by 2 on both sides, then the new equation will be 2x+2y=4 which is equivalent to x+y =2 .

So, from among all the choices given, the first choice represents the above mentioned property. The equation Fx + Gy = H is multiplied by 3 on both sides. So, the equation 3Fx + 3Gy = 3H is equivalent to Fx + Gy = H.

The second equation Qx + Ry = S has not been changed. So, the equivalent system of equations to the given system is:

3Fx + 3Gy = 3H\\Qx + Ry = S

o-na [289]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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Khan Acad
alexandr402 [8]

Answer:

7.222 (repeating)

Step-by-step explanation:

8 + 10 + 8 + 5 + 4 + 7 + 5 + 10 + 8 = 65

1      2    3    4    5    6    7    8     9

65 / 9 = 7.222 (repeating)

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=95%20%5Cdiv%2013.246" id="TexFormula1" title="95 \div 13.246" alt="95 \div 13.246" align="absm
Alexxx [7]

Answer:

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7 0
2 years ago
Read 2 more answers
Is the following shape a rectangle? How do you know?
pogonyaev
I would think it’s a square
7 0
2 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Olin [163]

Answer:

Step-by-step explanation:

in tri ADC and tri BDC

∠ADC =∠BDC = 90

DC is common

AD = BD (given)

triangle ADC ≅ tri BDC by SAS congruency

hence AC = BC by CPCT ( congruent parts of congruent triangles)

hence, BC = 13

8 0
3 years ago
Read 2 more answers
X^2 -9 divided by x+3
WINSTONCH [101]

Step-by-step explanation:

Hey, there!!

Given that,

\frac{ {x}^{2} - 9 }{x + 3}

{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.

\frac{ {x}^{2} -  {3}^{2}  }{x + 3}

We have a^2-b^2= (a+b) (a-b), so keep same formula on it.

\frac{(x + 3)(x - 3)}{(x + 3)}

(x+3) in numerator and denominator gets cancelled,

(x - 3)

Therefore, (x-3) is the final value.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
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