The mass of the N₂O in the given question is 92.4g.
<h3>What is the moles of N2O in the given conditions?</h3>
STEP1- Apply the ideal gas equation
PV=nRT
STEP2- Put the given values in the equation
P=130kPa, T=298K, V=40L R=8.31
STEP3- Solve the equation
N=PV/RT,
N=130×40/8.31×298
N=2.1moles
N=mass/molecular mass
mass=2.1×44
mass = 92.4g
Hence, the mass of N₂O is 92.4g.
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Answer:
12.5 g of Li are needed in order toproduce 0.60 moles of Li₃N
Explanation:
The reaction is:
6Li(s) + N₂(g) → 2Li₃N(s)
If nitrogen is in excess, the lithium is the limiting reactant.
Ratio is 2:6
2 moles of nitride were produced by 6 moles of Li
Then, 0.6 moles of nitride were produced by (0.6 .6)/ 2 = 1.8 moles of Li
Let's convert the moles to mass → 1.8 mol . 6.94 g/ 1mol = 12.5 g of Li
Explanation:
miscible liquids: water and alcohol
immiscible liquids: water and oil
https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equations/v/balancing-chemical-equations-introduction
this will help trust me
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