Answer:
v = 6.72 m/s
Explanation:
Given that,
Vertical height, h = 2.31 m
We need to find the speed at the bottom of the slide. Let the speed be v. We can find it using the conservation of energy such that,
Put all the values,
So, her speed at the bottom of the slide is equal to 6.72 m/s.
Answer:
3.75 seconds
Explanation:
Given:
y₀ = 2.00 m
y = 0 m
v₀ᵧ = 20.0 sin 60.0°
aᵧ = -9.8 m/s²
Find: t
y = y₀ + v₀ᵧ t + ½ aᵧ t²
0 = 2.00 + (20.0 sin 60.0°) t + ½ (-9.8) t²
0 = 2 + 10√3 t − 4.9 t²
Solve with quadratic method:
t = [ -10√3 ± √(300 − 4(-4.9)(2)) ] / -9.8
t = (-10√3 ± √378.4) / -9.8
t ≈ -0.218, 3.75
Since t > 0, the ball lands after approximately 3.75 seconds.