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bazaltina [42]
3 years ago
14

What is the frequency of a wave that has a speed of 0.6 m/s and a wavelength of 0.020 meter?

Physics
1 answer:
UNO [17]3 years ago
7 0
The formula for wave motion is speed of wave equals frequency times wavelength.v = f lambdarearrangingf = v/lambdaf = 0.6/0.02 = 60/2 = 30Hz, or cycles per second.
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Cells are the basic building block that makes up all living things. Cells are microscopic. What does this mean?
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Explanation:

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An object is accelerating if there is a change in speed and/or ________.
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A change in C. Direction.
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Four forces are exerted on a disk of radius R that is free to spin about its center, as shown above. The magnitudes are proporti
Dmitry_Shevchenko [17]

The given magnitude of forces of F₁ = F₄, F₂ = F₃, F₁ = 2·F₂, give the

forces that exert zero net torque on the disk as the options;

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<h3>How can the net torque on the disk be calculated?</h3>

The given parameters are;

F₁ = F₄

F₂ = F₃

F₁ = 2·F₂

Therefore;

F₄ = 2·F₂

In vector form, we have;

\vec{F_4} = \mathbf{\frac{\sqrt{3} }{2} \cdot F_4 \cdot \hat i -  0.5 \cdot F_4 \hat j}

\vec{F_2} = \mathbf{ -F_2 \,  \hat j}

Clockwise moment due to F₄, M₁ = -0.5 \times F_4 \,  \hat j  \times \dfrac{R}{2}

Therefore;

M_1  =- 0.5 \times 2 \times  F_2 \,  \hat j  \times \dfrac{R}{2} =   \mathbf{ -F_2 \,  \hat j  \times \dfrac{R}{2}}

Counterclockwise moment due to F₂ = -F_2 \,  \hat j  \times \dfrac{R}{2}

Given that the clockwise moment due to F₄ = The counterclockwise moment due to F₂, we have;

Two forces that combine to exert zero net torque on the disk are;

F₂, and F₄

Which are the options; (B) F₂, and (D) F₄

Learn more about the resolution of vectors here:

brainly.com/question/1858958

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2 years ago
What are the three factors needed for Newton’s Second Law?
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Answer:

the weight of the object, the force of gravity acting on said object, and the mass of the object are needed for Newton's second law of motion.

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3 years ago
S GP A projectile of mass m moves to the right with a speed vi (Fig. P11.51a). The projectile strikes and sticks to the end of a
Andrews [41]

What is the kinetic energy of the system after the collision?

K_f=\frac{3}{2} \frac{m^{2}v_i^{2}  }{(M+3m)}

How this is calculated?

Given:

Initial speed=v_i

mass of rod=M

Let, Initial kinetic energy =K_i

Final kinetic energy=K_f

Moment of inertia =I

What is the moment of inertia?

I=(I_p)_0+(I_{rod})_0\\I=m(\frac{d}{2})^{2}  +\frac{Md^{2} }{12} \\I=\frac{(M+3m)d^{2} }{12}

What is the angular momentum?

By conservation of angular momentum,

L_i=L_f

mv_i\frac{d}{2}=\frac{(M+3m)d^{2}\omega }{12}  \\\omega=\frac{6mv_i^{2} }{d(M+3m)}

We know that, the final kinetic energy is given by,

K_f=I\omega^{2}\\K_f=\frac{1}{2} *\frac{(M+3m)d^{2} }{12} *\frac{36m^{2}v_i^{2}}{d^{2}(M+3m)^{2}}\\ K_f=\frac{3}{2} \frac{m^{2}v_i^{2}  }{(M+3m)}

What is the kinetic energy?

  • In physics, the kinetic energy of an object is the energy that it possesses due to its motion.
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1 year ago
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