Answer:
13.4cm
Explanation:
According to Rayleigh’s criterion the angular resolution to distinguish two objects is given by:

θ = 50.0*10^-7 rad
λ: wavelength of the light = 550nm
b = diameter of the objective
By doing b the subject of the formula and replacing the values of the angle and wavelength you obtain:

hence, the smallest diameter objective lens is 13.4cm
Answer:
just search up a ven-diagram and then try to draw it or trace it then use it for ur question
Explanation:
B) not work ,because the water would freeze
The color components that will have the lowest index of refraction will be orange.