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Murrr4er [49]
3 years ago
9

Name the force between the brakes and the wheels that does work to slow down the vehicle when the brakes are applied. ​

Physics
1 answer:
suter [353]3 years ago
3 0

Answer:

Friction

Explanation:

Because the brake pad is rubbing alongside the wheel to slow the body of the car down

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A ball is dropped from rest from a Cliff and falls for 3 seconds.
trasher [3.6K]

Answer:

-29.4 m/s

Explanation:

Given:

v₀ = 0 m/s

t = 3 s

a = -9.8 m/s²

Find: v

v = at + v₀

v = (-9.8 m/s²) (3 s) + (0 m/s)

v = -29.4 m/s

4 0
4 years ago
Two electronics technicians are discussing conductors and insulators. Technician A says that conductors have more free electrons
vitfil [10]

Technician A is Correct.

You can see this when he says that conductors have more free electrons than insulators. This statement is True.

While Technician B says that, insulators have the lower resistance than conductors. This statement is False.

4 0
3 years ago
Read 2 more answers
It would be impossible to build a microscope that could use visible light to see the molecular structure of a crystal because. I
Serhud [2]

Answer:

the correct one is: a diffraction limits the resolving power to approximately the size of the wavelength of the light used

Explanation:

To be able to solve two structures with a light source, the Rayleigh criterion must be met that stable the two structures are solved when the first minimum of diffraction at one point is in the code of the first maximum of the other point

Using this criterion we can find an expression for the first minimization of the diffraction spectrum m = 1

     sin θ tea = λ / a

now the structure of the comatose has a separation of around 1 nm and the wavelength of visible light ranges from 400 to 700 nm, when substituting we find

           sin θ = 400/1 10

           sin θ  = 400

           sin θ  = 700/1

           sin θ  = 700

These values ​​are neither impossible since the sin function is bounded between -1 to 1, so we cannot see the diffraction

When reviewing the different statements, the correct one is: a diffraction limits the resolving power to approximately the size of the wavelength of the light used:

6 0
3 years ago
A charge Q is distributed uniformly around the perimeter of a ring of radius R. Determine the electric potential difference betw
il63 [147K]

Answer:

the electric potential difference between the point at the center of the ring and a point on its axis ΔV is ( 0.8356 )\frac{kQ}{R}

Explanation:

Given the data in the question;

electric potential at the center of the ring V₀ = kQ / R

electric potential on the axis point Vr = kQ / √( R² + x² )

at a distance 6R from the center,

point at x = 6R

so distance circumference r = √( R² + (6R)² )

so

electric potential on the axis point Vr = kQ / √( R² + (6R)² )

Vr = kQ / R√37

Now

ΔV = V₀ - Vr

we substitute

ΔV = ( kQ / R) - ( kQ / R√37 )

ΔV =  kQ/R( 1 - 1/√37 )

ΔV =  kQ/R( 1 - 0.164398987 )

ΔV =  kQ/R( 0.8356 )

ΔV = ( 0.8356 )\frac{kQ}{R}       { where k = \frac{1}{4\pi e_0} }

Therefore, the electric potential difference between the point at the center of the ring and a point on its axis ΔV is ( 0.8356 )\frac{kQ}{R}

5 0
3 years ago
Which of the following will increase the resistance of a wire? Check all that apply. Check all that apply. Increasing the cross-
Lostsunrise [7]

Correct answers:

- Increasing the resistivity of the material the wire is composed of will increase the resistance of the wire.

- Decreasing the cross-sectional area of the wire will increase the resistance of the wire.

- Increasing the length of the wire will increase the resistance of the wire.

Explanation:

The resistance of a wire is given by:

R=\rho \frac{L}{A}

where

\rho is the resistitivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

From the formula, we can notice that:

- The resistance (R) is directly proportional to both the resistivity (\rho) and the length of the wire (L), so when one of these quantities increases, the resistance will increase as well

- The resistance (R) is inversely proportional to the cross-sectional area (A), therefore when the resistance increases when the cross-sectional area decreases.

Based on these observations, the correct statements are:

- Increasing the resistivity of the material the wire is composed of will increase the resistance of the wire.

- Decreasing the cross-sectional area of the wire will increase the resistance of the wire.

- Increasing the length of the wire will increase the resistance of the wire.

7 0
3 years ago
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