Name the force between the brakes and the wheels that does work to slow down the vehicle when the brakes are applied.
1 answer:
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Answer:
a = 1 m/s² and
Explanation:
The first two parts can be seen in attachment
We use Newton's second law on each axis
Y axis
Ty - W = 0
Ty = w
X axis
Tx = m a
With trigonometry we find the components of tension
Sin θ = Ty / T
Ty = T sin θ
Cos θ = Tx / T
Tx = T cos θ
We calculate the acceleration with kinematics
Vf = Vo + a t
a = (Vf -Vo) / t
a = (20 -10) / 10
a = 1 m/s²
We substitute in Newton's equations
T Sin θ = mg
T cos θ = ma
We divide the two equations
Tan θ = g / a
θ = tan⁻¹ (g / a)
θ = tan⁻¹ (9.8 / 1)
θ = 84º
We see that in the expression of the angle the mass does not appear therefore you should not change the angle
Answer:
H = 54.37
Explanation:
given,
lead ball attached at = 1.70 m
rate of revolution = 3 revolution/sec
height above the ground = 2 m
circumference of the circle = 2 π r
= 2 x π x 1.7
= 10.68 m
v = 32.04 m/s
using conservation of energy
H = 54.37
the maximum height reached by the ball is equal to H = 54.37