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3 years ago

Will an object have the same weight on moon as it does ?

Physics

2 answers:

makkiz [27]3 years ago

8 0

Answer:

The mass of an object is the same everywhere either on earth or moon.

The weight of an object depends on a gravitational acceleration and it's different from one on earth and that on moon.

therefore the weight changes but the mass is the same.

Explanation:

Hope this helps

Ede4ka [16]3 years ago

3 0

Answer: The weight of an object is a force expressed in Newton (N). ... Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.

Explanation: Hope this helps :)

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4 years ago

Which imaging technique uses radiation that is emitted from the material being imaged

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Answer:

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4 years ago

Read 2 more answers

Write an expression for the magnitude of charge moved, Q, in terms of N and the fundamental charge e

NeTakaya

We have that for the Question "Write an expression for the magnitude of charge moved, Q, in terms of N and the fundamental charge e" it can be said its equation is

$Q=\frac{E}{Nr^2}$

From the question we are told

Write an expression for the magnitude of charge moved, Q, in terms of N and the fundamental charge e

<h3>An Expression for the magnitude of charge moved</h3>

Generally the equation for the magnitude of charge moved, Q is mathematically given as

$Q=\frac{E}{Nr^2}$

Therefore

An expression for the magnitude of charge moved, Q, in terms of N and the fundamental charge e" it can be

$Q=\frac{E}{Nr^2}$

For more information on this visit

brainly.com/question/16517842

3 0

2 years ago

The motor winds in the cable with a constant acceleration, such that the 20-kg crate moves a distance s = 6 m in 3 s, starting f

Marta_Voda [28]

Answer:

85 N

Explanation:

Given that crate mass = 20kg

Distance = 6m

Time = 3 seconds

Coefficient of kinetic friction = 0.3

We begin by calculating for acceleration

Which was gotten as 1.33 m/s sq

SEE THE ATTACHEMENT FOR DETAILS

8 0

4 years ago

Find the wavelength of the balmer series spectral line corresponding to n = 15.

Anna71 [15]

Answer:

371.2 mm

Explanation:

The Balmer series of spectral lines is obtained from the formula

1/λ = R(1/2² -1/n²) where λ = wavelength, R = Rydberg's constant = 1.097 × 10⁷ m⁻¹

when n = 15

1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)

= 1.097 × 10⁷ m⁻¹(1/4 -1/225)

= 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)

= 1.097 × 10⁷ m⁻¹ 0.245556

= 2.693 10⁶ m⁻¹

So,

λ = 1/2.693 10⁶ m⁻¹

= 0.3712 10⁻⁶ m

= 371.2 mm

7 0

3 years ago